Solve for a. √a−b+c=3 a=9+b−c a=3+√b−√c a=3+b−c a=9+√b−√c

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

5 0

Answer:

$\sqrt{a} = 3 + b - c$

Step-by-step explanation:

All you gotta do is subtract - b + c from both sides then simplify.

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Read 2 more answers

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$