3 years ago

Solve for a. √a−b+c=3 a=9+b−c a=3+√b−√c a=3+b−c a=9+√b−√c

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

5 0

Answer:

$\sqrt{a} = 3 + b - c$

Step-by-step explanation:

All you gotta do is subtract - b + c from both sides then simplify.

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3 years ago

Write a polynomial function that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of 2√ 13 and -2√13

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The polynomial function is $x^{2} - 52$

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A polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ .

In this problem:

The roots are $x_{1} = 2\sqrt{13}$ and $x_{2} = -2\sqrt{13}$

Then

$(x - 2\sqrt{13}) \times (x - (-2\sqrt{13})) = (x - 2\sqrt{13}) \times (x + 2\sqrt{13}) = x^{2} - 2x\sqrt{13} + 2x\sqrt{13} -(2\sqrt{13})^{2} = x^{2} - 52$

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