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2 years ago

Pleasse please please pleaseeee help me asap! thank you!

Mathematics

2 answers:

Rina8888 [55]2 years ago

7 0

I pretty sure it’s A

Darya [45]2 years ago

4 0

D. because 31/33 equals .93 repeating

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Help pls its been 30 minutes

Elina [12.6K]

Answer:

probability = 6/7

Step-by-step explanation:

a+b+c= 30 students

there are 35 students in total.

=30/35

30/35 fully simplified = 6/7

the probability that a student earns a grade of A, B, or C is 6/7.

also, 6/7 as a decimal rounded the nearest hundreth is 0.86, FYI.

6 0

3 years ago

Dustin has only nickels and quarters in his piggy bank. He has 49 coins total for a combined value of $8.85. How many of each ty

eduard

Well obviously quarters equal 25 cents. So you have to divide the 8.85 by 25 first. That means he could have 35 quarters. That least the rest as being dimes. So find the remaining amount of the 8.85. If you have 35 quarters that's $8.75. And 8.85 minus 8.75 is 10 cents. which would be 2 nickels. That only adds up 37 coins. So you break down one of the 25. That would mean 5 more coins could be nickels. Add 37 and 5 to get 42. Do it again. 25 cents in nickels would be 5 more coins. would be 46. that would be missing 2 coins. But don't forget you're also subtracting from the 35 quarters. Now you would technically have 12 nickels and 33 quarters. So you can do it one more time. 32 quarters means there is $8 in quarters at this point.

Now add you have 12 nickels, and you made 5 more. That's 17 nickels. That equals 85 cents. So add 17 and 32 to be sure you have 49 coins, which you do.

So 17 nickels, 32 quarters to equal 49 coins and $8.85

(sorry some of it got mixed up above because I was forgetting to subtract the quarters from the total as I changed them to nickels, so pay attention to the end)

8 0

3 years ago

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

1 year ago

A science fair poster is a rectangle 3 feet long and 2 feet wide. What is the area of the poster in square inches? Be sure to in

vredina [299]

Area = length · width
Area = 3ft · 2ft
Area = 6ft²

hope this helps!

5 0

3 years ago

In ΔCAB, point E is the midpoint of AC and point D is the midpoint of BC . If the measure of AB is 8 units, what is the measure

strojnjashka [21]

Answer:

4 units

Step-by-step explanation:

CAB and EAD are similar triangles with sides in the ratio 2:1

ED = ½ AB

½(8)

5 0

3 years ago

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