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Juliette [100K]
2 years ago
14

Will give brainliest

Mathematics
2 answers:
madam [21]2 years ago
3 0

i dont no but can someone help me on this???

Pick one thing about the U.S. Constitution including its amendments that you think should be changed. What modifications that you would make? Explain your reasons for making this change. Please write a 5 paragraph essay that details the changes

valentina_108 [34]2 years ago
3 0
The answer is b= - 4
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PLEASE HELP RN
yulyashka [42]

Step-by-step explanation:

y = -9x - 45 -5

y = -9x - 50

slope = x coefficient = -9

we can use the point where

x = 0

y = -50

P1 (0, -50)

and when y = 0

-9x = 50

x = -50/9

P2 = (-50/9 , 0)

3 0
2 years ago
Read 2 more answers
Find the product of the following
zhannawk [14.2K]

Answer:

1.

(a + 9) {}^{2}

2.

(6x + 2y) {}^{2}

3.

( \frac{4}{5} p + q) {}^{2}

4.

( \frac{2}{3} p +  \frac{3}{5} q) {}^{2}

5.

(y {}^{2}  + 3) {}^{2}

6.

( \frac{7}{9b {}^{2} }  + 2) {}^{2}

brainlist please please

4 0
2 years ago
What is the nth term rule of the quadratic sequence below? 7, 14, 23, 34, 47, 62, 79
Julli [10]

Answer:

Tn = Tn-1 + 2(n-1) + 5

Kindly note that Tn-1 means T subscript n-1

Step-by-step explanation:

Here, we want an expression for the nth term.

First term is 7

Then first common difference is 7

second common difference is 7 + 2

Third common difference is 9 + 2

So within the common differences, the nth term is 7 + (n-1) 2

Now, the nth term of the series would be;

Tn = Tn-1 + 7 + 2(n-1)

Tn = Tn-1 + 7 + 2n -2

Tn = Tn-1 + 2n + 5

Now there is a fix to this,

n for the term is not the same n for the common difference.

the 7th term works with the 6th common. difference, while the 8th term work for the 7th common difference.

So we might need to rewrite the final expression as follows;

Tn = Tn-1 + 2(n-1) + 5

6 0
3 years ago
Need help asap important! thanks so much!
a_sh-v [17]

Answer:

You would have $343.37 at the end of the 2 years.

Step-by-step explanation:

Interest earned is like bonus money the bank pays you just for keeping money

\mathrm{Compund\:Interest\:Formula}:\quad A =  P {  \left( 1+ \dfrac{ r  }{ n  }    \right)    }^{ nt  }

P: the starting balance of the account (also called initial deposit, or principal)

A: the new balance in the account after N years.

t: the number of years or time

r: the interest rate, (in decimal form)

n: the number of times the interest is compounded each year.

Annually = each year = 1

P =$300, r = 7%, t = 2, n = 1, A = ?

Substitute the numbers into the "Compound Interest Formula".

A =  300 {  \left( 1+ \dfrac{ 0.07  }{ 1  }    \right)    }^{ 1 \times  2  }

\mathrm{Anything\:divided\:by\:1\:gives\:itself}

A =  300 {  \left( 1+0.07  \right)    }^{ 1 \times  2  }

\mathrm{Add\:1\:and\:0.07\:to\:get\:1.07}

A =  300 \times   { 1.07  }^{ 1 \times  2  }

\mathrm{Multiply\:1\:and\:2\:to\:get\:2}

A =  300 \times   { 1.07  }^{ 2  }

\mathrm{Calculate\:1.07\:to\:the\:power\:of\:2\:and\:get\:1.1449}

A =  300 \times  1.1449

\mathrm{Multiply\:300\:and\:1.1449\:to\:get\:343.47}

A =  343.47

So you would have $343.37 at the end of the 2 years.

Look at the chart

\mathrm{Year}\quad \mathrm{Year\: Interest}\quad \mathrm{Total\:Interest}\quad \mathrm{Balance}\\\quad1\quad\quad\quad $21.00\quad\quad\quad\quad $21.00\quad\quad\quad\quad $321.00\\\quad2\quad\quad\quad $22.47\quad\quad\quad\quad $43.47\quad\quad\quad\quad $343.47

8 0
2 years ago
Please help me quickly
DaniilM [7]

Answer:

0.4

Step-by-step explanation:

Find square root of 12 and 15

12=3.46 rounded to 3.5

15=3.87 rounded to 3.9

0.9-0.5=0.4

5 0
2 years ago
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