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3 years ago

How would I plot (1,5) and (4,-1)

2 answers:

7 0

First number between parentheses is the x value and the second number is y value
so you plot the first value (x value) horizontally and the second value (y value) vertically

dmitriy555 [2]3 years ago

4 0

Answer:

To plot (1,5), start at the origin (0,0) and move right 1 unit and up 5 units.

(1,5)

To plot (4,−1) , start at the origin (0,0) and move right 4 units and down 1

units.

(4,−1)

List the points below:

(1,5),(4,−1)

Step-by-step explanation:

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bekas [8.4K]

Answer:

(1) $csc A=\dfrac{17}{8}$

(2) $sec A=\dfrac{17}{15}$

Step-by-step explanation:

$Tan A=\dfrac{8}{15}\\$In Trigonometry, $Tan A=\dfrac{Opposite}{Adjacent}\\$Therefore:\\Opposite=8, Adjacent=15$

Using Pythagoras theorem

$Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=8^2+15^2\\Hypotenuse^2=289\\Hypotenuse^2=17^2\\Hypotenuse=17$

Question 1

Now, cosecant = 1/sin

Therefore:

$csc A=\dfrac{Hypotenuse}{Opposite}\\csc A=\dfrac{17}{8}$

Question 2

Now, secant = 1/cos

Therefore:

$sec A=\dfrac{Hypotenuse}{Adjacent}\\sec A=\dfrac{17}{15}$

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4 years ago

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Paha777 [63]

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3 years ago

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Which line is perpendicular to the line 5y - 2x = 3?

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3 years ago

4+3x the (x has an exponent of 4)=81

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Answer:

x = 2.25 (Approximately)

Step-by-step explanation:

4 + 3x^4 = 81

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4 years ago

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How would I plot (1,5) and (4,-1)​

How would I plot (1,5) and (4,-1)