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guapka [62]
3 years ago
15

Find the area. Simplify your answer. 2x 3x

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
8 0

Answer:

We know,

Area of triangle = 1/2 * b * h

= 1/2 * 2x * 3x

= 1/2 * 6x

= 3x

Hope it helped

All the best !!

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A polynomial has zeros of -2 (with multiplicity 1) and 1 (with multiplicity 2). What is this
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Your first step would be to unsolve the zeros, which would leave you with x-1, x-1, and x+2. Then arrange the zeros in the position of a factored polynomial, such as (x-1)(x-1)(x+2), and then FOIL the first two terms. You would then end up with, x^2-2x+1(x+2). After this just finish unfactoring the polynomial.

Your answer would be:
1x^3+0x^2+-3x+2
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Expression equivalent to 3(7x + 9)
Sholpan [36]

Answer:

21x + 27

Step-by-step explanation:

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What is 1/2 of 1/5 =something
maksim [4K]
Half of 1/5 is 1/10. one tenth plus one tenth is one fifth
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3 years ago
The sum of two numbers is 87. The difference of the same to numbers is negative 111. Find the numbers.
anyanavicka [17]

Answer:

99 and - 12

Step-by-step explanation:

let x and y be the 2 numbers, then

x + y = 87 → (1)

x - y = - 111 → (2)

Adding the 2 equations term by term eliminates the y- term

2x = - 24 ( divide both sides by 2 )

x = - 12

Substitute x = - 12 into (1)

- 12 + y = 87 ( add 12 to both sides )

y = 99

The 2 numbers are 99 and - 12

5 0
3 years ago
Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

7 0
4 years ago
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