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Andrews [41]
3 years ago
9

Graph the following y−2=2/3(x+4)

Mathematics
1 answer:
lord [1]3 years ago
4 0
In the future you can go to desmos graphing calculator

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I need help i will mark brainlest
mafiozo [28]
B is the correct answer distributive property
7 0
3 years ago
The vertices of a triangle are A (2,5) B (1,2) and C (3,1) . Find the coordinates of the image after a dilation with respect to
telo118 [61]

K=2

  • A'=2(2.5)=(4,10)
  • B'=2(1,2)=(2,4)
  • C'=2(3,1)=(6,2)

Translation of 2 units left means change in x

  • A''=(4-2,10)=(2,10)
  • B"=(2-2,4)=(0,4)
  • C"=(6-2,2)=(4,2)

Translation of 1 units up means change in y

  • A'''=(2,10+1)=(2,11)
  • B'''=(0,4+1)=(0,5)
  • C'''=(4,2+1)=(4,3)
5 0
2 years ago
Read 2 more answers
ASAP WILL GIVE BRAINIEST TO FIRST PERSON TO ANSWER
aliya0001 [1]

Answer:

∠B = 22°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°, hence

120 + x + x + 16 = 180

2x + 136 = 180 ( subtract 136 from both sides )

2x = 44 ( divide both sides by 2 )

x = 22 = ∠B


4 0
3 years ago
What is 45 * 89 + 67 <55 - 56 =
gladu [14]

Answer:

False

Step-by-step explanation:

Use the order of operations

45 * 89 = 4005

4005 + 67 = 4072

55 - 56 = -1

4072 < -1

The answer is false.

4 0
3 years ago
Read 2 more answers
Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo
nlexa [21]

Given:

Equation of line 7x-4y=-12.

To find:

The equation of line  that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

7x-4y+12=0

Slope of line is

\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

m_1=-\dfrac{7}{(-4)}

m_1=\dfrac{7}{4}

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

m_1m_2=-1

m_2=-\dfrac{1}{m_1}

m_2=-\dfrac{4}{7}           [\because m_1=\dfrac{7}{4}]

Now, the slope of perpendicular line is m_2=\dfrac{4}{7} and it goes through (-21,2). So, the equation of line is

y-y_1=m_2(x-x_1)

y-2=-\dfrac{4}{7}(x-(-21))

y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)

y-2=-\dfrac{4}{7}x-12

y=-\dfrac{4}{7}x-12+2

y=-\dfrac{4}{7}x-10

Therefore, the required equation in slope intercept form is y=-\dfrac{4}{7}x-10.

7 0
4 years ago
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