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mihalych1998 [28]
2 years ago
9

Re-write the equation in Ax+By=C form. use integers for A,B, and C. y+2=-5(x-5)

Mathematics
1 answer:
Savatey [412]2 years ago
5 0

Answer:

5x+y=23

Step-by-step explanation:

y+2=-5(x-5)

y+2=-5x+25

y=-5x+25-2

y=-5x+23

23=y-(-5x)

23=y+5x

5x+y=23

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2 years ago
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

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Solutions are x = ± i and x = ± i\sqrt{5}

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2 years ago
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