Using the <u>normal approximation to the binomial</u>, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- The binomial distribution is the probability of <u>x successes on n trials</u>, with <u>p probability</u> of a success on each trial. It can be approximated to the normal distribution with
.
In this problem:
- 15% do not show up, so 100 - 15 = 85% show up, which means that
. - 300 tickets are sold, hence
.
The mean and the standard deviation are given by:


The probability that we will have enough seats for everyone who shows up is the probability of at most <u>270 people showing up</u>, which, using continuity correction, is
, which is the <u>p-value of Z when X = 270.5</u>.



has a p-value of 0.994.
0.994 = 99.4% probability that we will have enough seats for everyone who shows up.
A similar problem is given at brainly.com/question/24261244
Answer:
y=8
Step-by-step explanation:
substitute (plug in) 5 for x because it says that the value of x is 5
6y=-24x+120
simplified, it's
y=-4+20
Answer: 
Step-by-step explanation:
For this exercise you need to remember the Power of a power property. This states that:

You know that the given expression
is used to determine points earned, and "n" represents the game level.
Therefore, knowing this, you can to substitute
into the expression
:

Finally, in order to simplify the expression for the
level, you must apply the Power of a power property mentioned before.
Therefore, you get:
