Answer:
40 cm.
Step-by-step explanation:
Given,
height of the object = 10 cm
Distance of the object from the X-ray= 50 cm
Distance of detector from the source = 2 m = 200 cm
Height of the image, h = ?
Now,



Again applying


h = 40 cm
Hence, height of the image is equal to 40 cm.
The value of his investment at the third year is
F (3)=300×(1.02)^(3)=318.36
The value of his investment at the fifth year is
F (5)=300×(1.02)^(5)=331.22
The average rate of change of the value is
(331.22−318.36)÷2 years=6.43 per year
2(6.02*10^23)(3.35*10^-23)
2*6.02*3.35
answer : 4.0334*10^1