1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bija089 [108]
3 years ago
9

(SUPER EASY) ILL GIVE BRAINLIEST TOO. just answer all the questions you know.

Mathematics
2 answers:
IrinaK [193]3 years ago
8 0

Answer: x,y. 2,7, 1,

Step-by-step explanation:

g100num [7]3 years ago
8 0

Answer:

5.) (2,7)

6.) 0,3,4,6,8,9

7.) x= -4,-2,1

   y=2,-1,1

I hope this is good enough:

You might be interested in
Plz I don’t get this question your suppose to find the area
Zielflug [23.3K]

Answer:

25868.61 ft squared.

Step-by-step explanation:

First, find the area of the circle. Area equals pi times the value of the radius squared. Because there is only three quarters of the circle there, you need to divide the area by 4, and then multiply it by 3.

Then, for the rectangle, multiply the two numbers together to get the area. Just copy my answer, and you'll be fine.

7 0
3 years ago
Take your time but please answer quick.
omeli [17]
X> 1000/997
Alternate form is
x> 10 30/997, 1000/997 = 10.03009 , x {10000/997 , + infinity}
7 0
3 years ago
Read 2 more answers
A
telo118 [61]

Answer:

1 La longitud de las nuevas cuerdas = 5 metros y 9 metros

2 El costo de las paletas = $ 3

El costo de las gomitas = $ 3

Step-by-step explanation:

1) Sea la primera mitad de la cuerda representada por = a

Deje que la segunda mitad de la parte superior esté representada por = b

a + b = 14 metros

De la pregunta, se nos dice que ok, la mitad es 4 metros más larga que la otra

a = b + 4

Por lo tanto

b + 4 + b = 14 metros

2b + 4 = 14 metros

2b = 14 - 4

b = 10/2

b = 5 metros

a = b + 4

a = 5+ 4

a = 9 metros

Por lo tanto, la longitud de las nuevas cuerdas = 5 metros y 9 metros

2)

Representemos el costo de las paletas = p

Costo de gomitas = g

De la pregunta 2 se nos dice que:

Tu vas a la tienda con un amigo y compras 6 paletas y 2 gomitas. Si tú pagas $ 24

Por tanto: 6p + 2g = 24 ....... Ecuación 1

Tu amigo pide 1 paleta y 10 gomitas. y tu amigo $ 33

p + 10g = 33 ....... Ecuación 2

p = 33 - 10g

Sustituya p por 33 - 10g en la Ecuación 1

6p + 2g = 24 ....... Ecuación

6 (33-10 g) + 2 g = 24

198 - 60 g + 2 g = 24

-58g = 24-198

-58g = - 174

g = -174 / -58

g = $ 3

Para encontrar p

p = 33 - 10g

p = 33 - 10 × 3

p = 33 - 30

p = $ 3

Por lo tant,

El costo de las paletas = $ 3

El costo de las gomitas = $ 3

6 0
3 years ago
Please help, I need the answer
Oxana [17]
9189.15 ft (this is the answer and I have not rounded it)
6 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-3,5) and has a slope of -2
wariber [46]

Answer:

equation: y=-4x-7

Step-by-step explanation:

y=-4x+b

solve for b using given coordinates on the line (-3, 5)

5=-4(-3)+b

b=-7


6 0
4 years ago
Read 2 more answers
Other questions:
  • A map has a scale of 1 cm : 11.5 km. Two cities are 5.5 cm apart on the map. To the nearest tenth of a kilometer, what is the ac
    9·1 answer
  • -x+7y=5,-4x+y=-7 <br> System of equations substitution
    9·1 answer
  • Simplify the following expression
    12·1 answer
  • Which of the following elevations are deeper than -200 feet? Select all that apply.
    12·2 answers
  • Someone help me please?
    9·1 answer
  • Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    6·2 answers
  • What is the distance between the bakery (b) and the library (c)? Explain using coordinate subtraction
    5·1 answer
  • Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form. 4, 2, 1
    13·1 answer
  • Solve for x as well as rounding to nearest tenth please&lt;3
    13·1 answer
  • X(x - 5) = -4<br><br> Solve the equation, using the quadratic formula.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!