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3 years ago

(SUPER EASY) ILL GIVE BRAINLIEST TOO. just answer all the questions you know.

Mathematics

2 answers:

IrinaK [193]3 years ago

8 0

Answer: x,y. 2,7, 1,

Step-by-step explanation:

g100num [7]3 years ago

8 0

Answer:

5.) (2,7)

6.) 0,3,4,6,8,9

7.) x= -4,-2,1

y=2,-1,1

I hope this is good enough:

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Elza [17]

Answer:

$P(W') = \frac{6}{n+6}$

Step-by-step explanation:

Let P(W) represents the probability that Paul wins

Let P(W') represents the probability that Paul does not win

Given

$P(W) = \frac{n}{n+6}$

Required

$P(W')$

In probability, the sum of opposite probability equals 1;

This implies that

$P(W) + P(W') = 1$

Substitute $P(W) = \frac{n}{n+6}$ in the above equation

$P(W) + P(W') = 1$ becomes

$\frac{n}{n+6}+ P(W') = 1$

Subtract $\frac{n}{n+6}$ from both sides

$\frac{n}{n+6} - \frac{n}{n+6} + P(W') = 1 - \frac{n}{n+6}$

$P(W') = 1 - \frac{n}{n+6}$

Solve fraction (start by taking the LCM)

$P(W') = \frac{n + 6 - n}{n+6}$

$P(W') = \frac{n - n + 6}{n+6}$

$P(W') = \frac{6}{n+6}$

Hence, the probability that Paul doesn't win is $P(W') = \frac{6}{n+6}$

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3 years ago

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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