Using the z-distribution, it is found that a sample size of 1066 is required.
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which z is the z-score that has a p-value of .
The margin of error is:
From the previous study, the estimate is of 0.23, hence .
98% confidence level, hence, z is the value of Z that has a p-value of , so .
The sample size is <u>n for which M = 0.03</u>, hence:
Rounding up, a sample size of 1066 is required.
A similar problem is given at brainly.com/question/12517818
Answer:
4 people went to the movie
Step-by-step explanation:
subtract 18 from 52
$34
divide that by $8.50 a ticket
=4
Note that f(1) = 6(1)+2 = 8. Next, evaluate g(x) at x=8: g(f(1)) = g(8) = 2(8) + 4/5, or 16 4/5.
Answer:
There were 16 birds at the shelter on Wednesday.
Step-by-step explanation:
Number of cats and birds on Wednesday = 34
let the number of birds on Wednesday = b
Then number of cats = (34 -b)
The rate of taking care of each bird in shelter = $3
The rate of taking care of each cat in shelter = $7
Total amount spent by shelter on Wednesday = $174
So, according to the question
b x ($3) + (34 -b) ($7) = $ 174
or, 3b + 238 - 7b = 174
or, 4b = 64
⇒ b = 64/4 = 16
Hence, the number of birds in shelter on Wednesday = b = 16
and Number of cats = 34 - 16 = 18
Answer:
b =
Step-by-step explanation:
35b = 7
Divide both sides by 35.
Reduce the fraction to the lowest terms by extracting and canceling out 7.
Hope it helps and have a great day! =D
~sunshine~