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3 years ago

Does anyone know if it is a positive, negative, or non?

Mathematics

2 answers:

const2013 [10]3 years ago

8 0

Answer:

Positive

Step-by-step explanation:

Hope this helps

Dmitrij [34]3 years ago

3 0

It is a Positive trend because it is goin up in the positive direction

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Convert the following measurements round your decimal places. 14,974 pounds to tons

Kitty [74]

Answer:

7.487 tons

Step-by-step explanation:

There are 2,000 pounds in one ton, so you divide 14,974 by 2,000 to get your answer.

6 0

4 years ago

Read 2 more answers

Which of the following expressions are equivalent to 312?

lord [1]

Answer:

3(4+3^2)×8

Step-by-step explanation:

Evaluate the power

3(4+9)×8

Add the numbers 3×13×8

Calcuate the product and it will be 312

So the expression 3×(4+3^2)×8 are equivalent to 312

Hope this helpsʕ•ᴥ•ʔ

4 0

3 years ago

Brian invests £8500 into his bank account.

iragen [17]

8500*1.057==??
??*1.057==??
6 times
You will have in 6 years £11854,1072

8 0

4 years ago

Read 2 more answers

In the following exercises, translate into an equation and solve

Citrus2011 [14]

Answer: 6 children

Step-by-step explanation:

Given:

Children - 24

Groups - 4

Number of children per group - x

Solve:

24 ÷ 4 = x

x = 6

Hope it helps!!! Please mark as brainliest. Thanks :D

7 0

2 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

4 years ago