<h2>Hey there!</h2>
<h3>At first we have find the value of "y",</h3>
<h3>Finding the value of "y"</h3>
Here,
8x + y = 23 - 10x - y = - 27
10(8x + y) = 23 × 10 8 (- 10x - y) = - 27 × 8
80x + 10y = 230 ---> (i) - 80x - 8y = - 216 ----> (ii)
<h3>By elimination method,</h3>
<h3>Equation (i) - (ii)</h3>
(80x + 10y) - (-80x - 8y) = 230 - (-216)
=> 80x + 10y + 80x + 8y = 230 + 216
=> 10y + 8y = 446
=> 18y = 446
=> y = 446/18
=> y = 24.7
<h3>Putting the value of "y" in Equation (i)</h3>
80x + 10y = 230
=> 80x + 10 × 24.7 = 230
=> 80x + 247 = 230
=> 80x = 230 - 247
=> 80x = -17
=> x = -17/80
=> x = - 0.21
<h3>Therefore the values of "x" and "y" are</h3>
x = -0.21 and y = 24.7
<h2>Hope it helps </h2>
Let n be the amount of fat for the 90 lb person. Then:
78/117=90/n
78n=10530
n=135g for a 90 lb person
☺☺☺☺
Answer:
Cat owner Dog owner Total
Wet food 9 13 22
Dry food 10 14 24
Total 19 27 46
Step-by-step explanation:
It is given that 9 cat owners and 13 dog owners chose "Wet food". 10 cat owners and 14 dog owners chose "Dry food".
Cat owners-Wet food = 9
Dog owners-Wet food =13
Cat owners-Dry food = 10
Dog owners-Dry food =14
We need to construct a two-way frequency table for the data.
Take owners in the first row and type of food in first column and construct a two-way frequency as shown below:
Cat owner Dog owner Total
Wet food 9 13 22
Dry food 10 14 24
Total 19 27 46
Answer:
he worked 40 hours on the the weekdays
Step-by-step explanation:
