Answer:
66-18=28+20
Step-by-step explanation:
Answer:

Step-by-step explanation:
3 different china dinner sets, each consisting of 5 plates consist of 15 plates.
A customer can select 2 plates in

different ways.
2 plates can be selected from the same dinner set in

different ways.
Thus, the probability that the 2 plates selected will be from the same dinner set is

6×4=24
You keep change flip.
So you change ÷ to ×
And flip 1/4 to 4.
So it is 6×4=24
Answer:
a) 7a/8; b) 5a/8
Step-by-step explanation:
Given:
AP = 2PQ = 2QB
Calculations:
1. A to the midpoint of QB
a = AP + PQ + QB
If 2PQ = 2QB.
PQ = QB and
AP = 2PQ
∴ a = 2PQ + 2PQ = 4PQ
PQ = a/4
AP = 2PQ = a/2
Let M be the midpoint of QB.
AM = AP + PQ + QM
= a/2 + a/4 + a/8
= 7a/8
2. Midpoints of AP and QB
Let N be the midpoint of AP
NM = NP + PQ + QM
= a/4 +a/4 + a/8 =
= 5a/8