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liraira [26]
3 years ago
15

harrison pours sand into a bucket at a constant rate. the graph shows the total weight of the bucket and the sand over time. aft

er 10 seconds, the total weight is 50 ounces what is an equation of the line parrallel to the line on the graph that passes to the graph that passes through (2, 25)
Mathematics
1 answer:
mash [69]3 years ago
7 0

Answer:

The answer is "\bold{y=4x+17}".

Step-by-step explanation:

In the given statement the graph is missing. So, the correct solution to this question can be described as follows:

Given

graph point: \bold{(2, 25)}

Line points: \bold{(0,10), \ \  and \ \ (10,50)}

The Formula of slope:

\boxed{M= \frac{y_2-y_1}{x_2-x_1}}\\\\\Rightarrow x_1= 0, y_1= 10 \\\\\Rightarrow x_2= 10, y_2=50\\\\\Rightarrow M= \frac{50-10}{10-0}\\\\\Rightarrow M=\frac{40}{10}\\\\\Rightarrow M= 4\\

Assuming  point: (x,y)

Graph point: (2,25)

M= 4

Equation:

\Rightarrow \frac{25-y}{2-x}=4\\\\\Rightarrow 25-y=4(2-x)\\\\\Rightarrow 25-y=8-4x\\\\\Rightarrow y= 4x-17\\

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------------------------------------------------------------------
Question
------------------------------------------------------------------
\boxed { \frac{n+h}{5}  =  \frac{f+9}{9}}

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Split the fraction on the left
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\boxed { \frac{n}{5} + \frac{h}{5}  = \frac{f + 9}{9}}

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Take away h/5 from both sides
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\boxed { \frac{n}{5}  = \frac{f+9}{9} - \frac{h}{5}}

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Change the denominator to be the same
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Rearrange (This step may not be necessary)
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\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }


\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}

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