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yulyashka [42]
3 years ago
8

- ignore this :) thank you v much.

Mathematics
1 answer:
yan [13]3 years ago
8 0

Answer:

i dont know what you mean by ignore this and it looks like you got it

Step-by-step explanation:

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In the past, professional baseball was played at the Astrodome in Houston, Texas. The Astrodome has a maximum height of 63.4 m.
8_murik_8 [283]

Answer:

The correct value of the h function is; h= -9.8t² + 45t + 1

Using the discriminant, no real solution exists and the baseball will not hit the roof

.Step-by-step explanation:

h= -9.8t² + 45t + 1

Astrodome has a maximum height of 63.4 m

find out if the baseball hit at a velocity of 45 m/s will hit the roof, we'll replace h with 63.4m.

Thus;

63.4 = -9.8t² + 45t + 1

Subtract 63.4 from both sides to give;

-9.8t² + 45t + 1 - 63.4 = 0

-9.8t² + 45t - 62.4 = 0

Using quadratic formula, we have;

t = -45 ± √{(45² - (4 * (-9.8) * (-62.4)}

t = -45 ± √(2025 - 2446.08)

t = -45 ± √(-421.08)

The discriminant is -421.08

This value is less than 0.

Thus, no real solution exists and the baseball will not hit the roof.

8 0
3 years ago
On a field trip a 6th grade class traveled 19.95 kilometer by train, 7 kilometer by bus and 2.3 kilometer by car. How far did th
CaHeK987 [17]
 19.95 + 7 + 2.3 = 29.25 kilometers
7 0
3 years ago
What is 7p-(-5)+(-1)
nika2105 [10]
7p-(-5)+(-1)
7p+5-1
7p+4
7 0
3 years ago
Read 2 more answers
Find the arc length with the given information <br> central angle=pi/4 radius=2
Ipatiy [6.2K]

Answer:1.57

Step-by-step explanation:

6 0
3 years ago
A camera manufacturer spends $1500 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell f
Reil [10]

Answer:

a)The company has to 250 cameras in one day to equal its daily cost

b)Their daily profit  will be $400

Step-by-step explanation:

Given:

overhead expenses = $1500

labour and materials expenses = $9

cameras sell for $15 each

To Find:

(a)How many cameras must the company sell in one day to equal its daily cost

(b) If the manufacturer can increase production by 50 cameras per day, what would their daily profit be?

Solution:

a) let the number of cameras sold per day be x

Total daily cost = overhead expenses +labour and materials expenses

Total daily cost = 1500 + 9x--------------------------(1)

Total daily revenue = 15x------------------------------(2)

Equating (1) and (2)

1500 + 9x = 15x

1500 = 15x- 9x

1500 = 6x

x= \frac{1500}{6}

x= 250

So, the company has to 250 cameras in one day to equal its daily cost.

b) increasing production by 50 cameras per day will give a daily profit of

=>50 X (17-9)

=>50 X 8

=> 400

5 0
3 years ago
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