The first step to do is to arrange the data set from least to greatest.
72 80 83 85 88 90 91 92 93 94
From the arrangement, we can see that the minimum is 72 and the maximum is 94. Next, the median is the middle number of the data. Since there are 10 data points, we take the average of the middle 2 numbers. The median is (88+90)/2 = 89.
When you talk about the quartiles, you draw divisions in your set. Q₁ is the middle data between the smallest and the median; Q₂ is the median; and Q₃ is the middle data between the largest and the median.
72 80 83 85 88 | 89 | 90 91 92 93 94
Q₁ is 83
Q₂ is 89
Q₃ is 92
Therefore, in summary, the answer is: <span>Minimum = 72, Q1 = 83, median = 89, Q3 = 92, maximum = 94</span>
Answer:
I think 21/12
Step-by-step explanation:
<em>hope</em><em> it</em><em> works</em><em> out</em><em>,</em><em>!</em><em>!</em>
This problem fits the conditional probability formula very well. The formula is P(B|A) = P(B ∩ A)/P(A). If event A is winning the first game, and event B is winning the second, then P(B ∩ A) = 0.44, and P(A) = 0.6. So P(B|A) is obtained by dividing 0.44 by 0.6, which is about 0.733.