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kirill [66]
3 years ago
15

What is an equation of the horizontal asymptote or slant asymptote of the function f(x)=−8x2 + 54x − 474x − 5?

Mathematics
1 answer:
RSB [31]3 years ago
8 0

Answer:

89

Step-by-step explanation:

I took the same exact test 9

You might be interested in
PLEASE PLEASE PLEASE HELP!!
irga5000 [103]
  9            a
------  =  -----
  a            5

a^2 = 45 

a = 3<span>√5
</span>
  4            b
------  =  -----
  b            5

b^2 = 20

b = 2√5

answer: 

a = 3√5
b = 2√5

hope it helps
7 0
3 years ago
A bus driver pays all tolls, using only nickels and dimes, by throwing one coin at a time into the mechanical toll collector.
lutik1710 [3]

Answer: a) An = An-1 + An-2

b) 55ways

Step-by-step explanation:

a) a nickel is 5 cents and a dime is 10cent so a multiple of 5 cents is the possible way to pay the tolls in both choices.

Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that

An = 5n cents

Case 1: Using a nickel for payment which is 5 cents, the number of ways given as;

An-1 = 5( n-1)

Case 2: using a dime which is two 5 cents, the number of ways is given as;

An-2 = 5(n-2)

Summing up the number of ways, we have

An = An-1 + An-2

From the relation,

If n= 0, Ao= 1

n =1, A1= 1

b) 45 cents paid in multiples of 5cents will give us 9 ways(A9)

From the relation, we have that

Ao = 1

A1 = 1

An =An-1 + An-2

Ao = 1

A1 = 1

A2 = A1+Ao = 1+1= 2

A3 = A2 + A1 = 3

A4 = A3+A2=5

A5=A4+A3=8

A6=A5+A4=13

A7 =A6+A5 = 21

A8= A7+A6= 34

A9= A8+A7= 55

So there are 55ways to pay 45cents.

4 0
3 years ago
How many solutions does this linear system have?
Tanya [424]

Answer:

B (2.5, 0)

Step-by-step explanation:

2x - y = 5 (multiply all by 4)

8x- 4y = 20

-8x - 4y = - 20

eliminate the 4y

8x- 4y = 20

-8x - 4y = - 20

-------------------- –

16x = 40

x = 40/16 = 2.5

now we substitute x with 2.5

2x - y = 5

2(2.5) - y = 5

y = 0

8 0
4 years ago
Someone help. (Find the area of a rectangle with a lenght of 5a^2 b^4 and a width of (3ab^3)^2
Dmitry_Shevchenko [17]

Answer:

All you do is just multiply them.

Step-by-step explanation:

5a^2 b^4(3ab^3)^2=

45(a^(4))(b^(10))

3 0
3 years ago
I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ
kumpel [21]

Answer:

side of 6.124 ft and height of 3.674 ft

Step-by-step explanation:

Let's s be the side of the square base and h be the height of the rectangular box.

The base and the roof would have an area of s^2 and cost of

4s^2 + 2s^2 = 6s^2

The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh

So the total cost for the material is

6s^2 + 10sh = 450

10sh = 450 - 6s^2

h = 45/s - 0.6s

The volume of the shed has the following formula

V = s^2h = s^2(45/s - 0.6s) = 45s - 0.6s^3

To find the maximum value for V, we can take its first derivative, and set it to 0

\frac{dV}{ds} = 45 - 1.2s^2 = 0

1.2s^2 = 45

s^2 = 45 / 1.2 = 37.5

s = \sqrt{37.5} = 6.124 ft

h = 45/s - 0.6s = 3.674 ft

4 0
4 years ago
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