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Yakvenalex [24]
3 years ago
10

I need someones help !!!!!!!!ASAPPP

Mathematics
2 answers:
alexira [117]3 years ago
5 0

Answer:

c

Step-by-step explanation:

stealth61 [152]3 years ago
4 0
The answer would be C
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Answer:Yes i do

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Determine whether the following events are mutually exclusive:
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non mutually exclusive event

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Which two of the following have the same value as 4.032?
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I need help, pls and thx
Sauron [17]

The solutions for the quadratic equation are given as follows:

x = -1, x = 7/5

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

For this problem, the equation is:

5x² - 2x - 7 = 0.

Hence the coefficients are a = 5, b = -2 and c = -7, and then the solutions are found as follows:

  • \Delta = (-2)^2 - 4(5)(7) = 144
  • x_1 = \frac{2 + \sqrt{144}}{10} = \frac{7}{5}
  • x_2 = \frac{2 - \sqrt{144}}{10} = -1

The solutions are:

x = -1, x = 7/5

More can be learned about quadratic equations at brainly.com/question/24737967

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7 0
2 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
3 years ago
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