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nydimaria [60]
3 years ago
14

Which equation is equivalent to -y + 2y - 9 = 1 ? y=8

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0
<h2>answer</h2><h3>y=14 or 8</h3>

<h2>i HOPE IT'S HELP </h2><h2 />

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Match each p to the correct £ amount
Serjik [45]
500p=5.00 50p=0.50 5p=0.05
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3 years ago
The weight of the rectangle is 80
Helga [31]

Answer:

6 2/3

Step-by-step explanation:

7 0
3 years ago
Which ratio is greater than 11/16?
OleMash [197]
3/4 is great if thats on of your answers because it was one of mine
5 0
3 years ago
10. Read the question carefully and type your answer in the space below. *
Korolek [52]

Answer:

Greatest = 98,321

Least= 12,389

98,321>12,389

Step-by-step explanation:

there are only 5 digits. To get the greatest number, the digits with the most value should be put in front to ensure the great value.

To get the smallest number, the digits with the least value should be put in front.

The greater valued number is greater than the least valued number

5 0
3 years ago
A 0. 0427 kg racquetball is moving 22. 3 m/s when it strikes a stationary box. The ball bounces back at 11. 5 m/s, while the box
andreyandreev [35.5K]

To solve the question we must know about the conservation of momentum.

<h2>Conservation of Momentum</h2>

According to the law of conservation of momentum, when two bodies collide with each other then their momentum is conserved if no external force acts on the system. therefore, the combined momentum of the two objects before collision will be equal to the combined momentum of the two objects after the collision.

the momentum of the two objects before the collision

                       = momentum of the two objects after the collision

The mass of the box is 0.30141 kg.

<h2>Explanation</h2>

Given to us

  • Mass of racquetball, m = 0.0427 kg,
  • Velocity of racquetball before Collision,  \bold{u_1} = 22.3 m/s,
  • Velocity of box before Collision,\bold{ u_2}  = 0 m/s,
  • Velocity of racquetball after Collision, \bold{v_1} = 11.5 m/s,
  • Velocity of box after Collision, \bold{v_2} = 1.53 m/s,

<h3>Assumption</h3>

Let the mass of the box be M.

<h3>Conservation Of Momentum</h3>

Momentum before collision = Momentum after collision

mu_1 + Mu_2 = mv_1 + Mv_2

given, the box was stationary before the collision,

mu_1 + Mu_2 = mv_1 + Mv_2\\\\&#10;mu_1 + 0 = mv_1 + Mv_2\\\\&#10;mu_1  - mv_1 = Mv_2\\\\&#10;M= \dfrac{mu_1  - mv_1}{v_2}

Substituting the values,

M= \dfrac{mu_1  - mv_1}{v_2}\\\\&#10;M = \dfrac{(0.0427 \times 22.3)  - (0.0427\times 11.5)}{1.53}\\\\&#10;M = 0.30141\ kg

Hence, the mass of the box is 0.30141 kg.

Learn more about Conservation of Momentum:

brainly.com/question/2141713

3 0
3 years ago
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