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xxTIMURxx [149]
2 years ago
13

Which of the fractions shown has the greatest value? 24 47 13 49

Mathematics
2 answers:
tresset_1 [31]2 years ago
8 0
Answer:

i’m pretty sure it should be 49..?
Vitek1552 [10]2 years ago
7 0
I think is 49 since is the bigger number lol
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Three exterior angles of a pentagon measures 60,80and 90.Find the measure of other two exterior angle, assuming them equally Tha
julsineya [31]

Given:

The three exterior angles of a pentagon measures 60,80 and 90.

To find:

The measure of other two exterior angle, assuming them equally.

Solution:

Let x be the measure of two other exterior angles of the pentagon.

We know that the sum of all exterior angles of a pentagon is 360 degrees.

60^\circ+80^\circ+90^\circ+x+x=360^\circ

230^\circ+2x=360^\circ

2x=360^\circ-230^\circ

2x=130^\circ

Divide both sides by 2.

\dfrac{2x}{2}=\dfrac{130^\circ}{2}

x=65^\circ

Therefore, the measures of both exterior angles are 65 degrees.

6 0
2 years ago
What kinds of cells would you expect to find full of ribosomes?
wariber [46]
Eukaryotic<span> cells would be full of ribosomes.</span>
5 0
3 years ago
The width of a rectangle is 7y -7.5 feet and the length is 7.5y + 8 feet. Find the perimeter of the rectangle
galben [10]

Perimeter = length + length + width + width.

7y-7.5 + 7y-7.5 + 7.5y+8 + 7.5y +8

Combine like terms:

29y+1

The perimeter is 29y + 1 feet

5 0
2 years ago
Kris has 4 yards of ribbon. it takes 2/3 yard to wrap one package. How many packages can Kris wrap?
Serggg [28]

Answer:

C. 6 packages

Step-by-step explanation:

4 divided by 2/3

=>4x3/2=6

mark me as the brainliest plz

3 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
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