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3 years ago

DUE IN 3 mins C-9 at C= 16

Mathematics

2 answers:

bixtya [17]3 years ago

8 0

7.
If c = 16
that means the equation is
16 - 9
which is 7
so 7

Ratling [72]3 years ago

4 0

Answer:

Step-by-step explanation:

plug 16 in for c so it's 16 -9 = 7

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Which is M=9pm solved for p

zaharov [31]

<h2>Answer:</h2>

<u>The value of </u><u>p :M/9m</u>

<h2>Explanation:</h2>

As we have been given value of M

Value of M=9pm

So we can find value of p from here by simple mathematics rule

M=9pm

divide both side with 9m so

M/9m=9pm/9m

we get value of p so M/9m=p.

we can write it as p=M/9m

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tiny-mole [99]

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2 years ago

PLEASE HELP! POINTS!<br><br><br> Graph y = – 4/3x + 1

9966 [12]

I'm kind of thrown off for that negative sign, but I try it out in the one that makes sense is this one [ https://gyazo.com/192a76e70d2d46979691cabbf06e6c85 ] If you can better of explain where the negative sign will be great. Hope I helped.

4 0

3 years ago

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

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3 years ago

Using the extreme value theorem, which graph has a maximum of 3 and minimum of –9?

klasskru [66]

Answer:

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Step-by-step explanation:

7 0

3 years ago

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