Question

The length of a rectangle is 3 less than twice the width. If the area of the rectangle is 50 square inches, choose the equation that could be used to solve for the dimensions.

Answer 1

Answer:

$w(2w-3)=50$

Explanation:

Let the length of the rectangle be $w$ units.

We were given that the length is 3 less than twice the width.

This implies that: $l=2w-3$

We have that the area of this rectangle is 50  square inches.

Recall that area of rectangle is given by:

$A=lw$

$\implies w(2w-3)=50$

Therefore the required equation is $w(2w-3)=50$