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adoni [48]
3 years ago
15

The length of a rectangle is 3 less than twice the width. If the area of the rectangle is 50 square inches, choose the equation

that could be used to solve for the dimensions.
Advanced Placement (AP)
1 answer:
USPshnik [31]3 years ago
6 0

Answer:

w(2w-3)=50

Explanation:

Let the length of the rectangle be w units.

We were given that the length is <em>3 less than twice the width.</em>

This implies that: l=2w-3

We have that the area of this rectangle is 50  square inches.

Recall that area of rectangle is given by:

A=lw

\implies w(2w-3)=50

Therefore the required equation is w(2w-3)=50

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