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harkovskaia [24]
3 years ago
9

Please help **if you don't know please, please don't answer** which of these representations show y as a function of x

Mathematics
1 answer:
boyakko [2]3 years ago
8 0
Dis the correct answer
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Through: (1,5), slope = 3
Svet_ta [14]

Answer:

The answer is y=3x+2

Step-by-step explanation:

y-y=m(x-x¹)

y-5=3(x-1)

y-5=3x-3

+5 +5

y=3x+2

4 0
3 years ago
A cube consists of twenty-seven 2 x 2 x 2-inch small cubes. One of the corner
AysviL [449]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t^3 + 21t^2 + 60t + 3 for t ≥ 0 with t measured in
natta225 [31]
As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.

Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.

\bf s(t)=2t^3-21t^2+60t+3\implies \boxed{\cfrac{ds}{dt}=6t^2-42t+60}\leftarrow v(t)
\\\\\\
0=6t^2-42t+60\implies 0=t^2-7t+10\implies 0=(t-5)(t-2)
\\\\\\
t=
\begin{cases}
5\\
2
\end{cases}\impliedby \textit{it makes the first turn at the \underline{2 second}}
\\\\\\
\textit{now let's find the acceleration equation, a(t)}
\\\\\\
\boxed{\cfrac{d^2s}{dt^2}=12t-42}\leftarrow a(t)\\\\
-------------------------------\\\\
s(2)=55\qquad \qquad \qquad \qquad a(2)=-18

the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.
8 0
3 years ago
A penny
enyata [817]

Answer:

320mph

Step-by-step explanation:

3 0
2 years ago
In a survey of 155155 senior​ executives, 48.448.4​% said that the most common job interview mistake is to have little or no kno
victus00 [196]

Answer:

We conclude that in the population of all senior​ executives, different from 40​% say that the most common job interview mistake is to have little or no knowledge of the company.

Step-by-step explanation:

We are given that in a survey of 155 senior​ executives, 48.4% said that the most common job interview mistake is to have little or no knowledge of the company.

We have to use a 0.05 significance level to test the claim that in the population of all senior​ executives, 40% say that the most common job interview mistake is to have little or no knowledge of the company.

Let p = <u><em>population proportion of senior​ executives who said that the most common job interview mistake is to have little or no knowledge of the company</em></u>

So, Null Hypothesis, H_0 : p = 40%     {means that in the population of all senior​ executives, 40​% say that the most common job interview mistake is to have little or no knowledge of the company}

Alternate Hypothesis, H_A : p \neq 40%     {means that in the population of all senior​ executives, different from 40​% say that the most common job interview mistake is to have little or no knowledge of the company}

The test statistics that would be used here <u>One-sample z test for proportions</u>;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of senior​ executives who said that the most common job interview mistake is to have little or no knowledge of the company = 48.4%

            n = sample of senior​ executives = 155

So, <u><em>the test statistics</em></u>  =  \frac{0.484-0.40}{\sqrt{\frac{0.484(1-0.484)}{155} } }  

                                       =  2.09

The value of z test statistics is 2.09.

<u>Also, P-value of the test statistics is given by;</u>

         P-value = P(Z > 2.09) = 1 - P(Z \leq 2.09)

                       = 1 - 0.9817 = <u>0.0183</u>

<u>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that in the population of all senior​ executives, different from 40​% say that the most common job interview mistake is to have little or no knowledge of the company.

4 0
4 years ago
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