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3 years ago

Identify an example of economic activity that is not included in GDP?

Geography

1 answer:

aev [14]3 years ago

6 0

Answer:

Here is a list of items that are not included in the GDP: Sales of goods that were produced outside our domestic borders. Sales of used goods. Illegal sales of goods and services (which we call the black market)

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Colombia is located at number _____ on the map above, and Chile is located at number _____.

inysia [295]

Answer:

D. 1 . . . 5

Colombia is located at number 1. and Chile is located at 5.

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3 years ago

Read 2 more answers

Is the Robinson map a reliable source for geographers to study the earth?

Ludmilka [50]

Yes it is a reliable source

Explanation: it shows the earth all in one. Makes it easier to study

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2 years ago

What are the differences and similarities between topographic maps and orthophoto maps in terms of data source used to create th

Anit [1.1K]

<span>The correct answer for the question that is being presented above is this one: "Topographic maps feature contour lines to portray the shape and elevation of the land. Topo maps render the three-dimensional ups and downs of the terrain on a two-dimensional surface. It also includes contours. Orthophoto maps</span> show land features using color-enhanced photographic images which have been processed to show detail in true position. They may or may not include contours."

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3 years ago

Why are climate graphs good?

salantis [7]

Explanation:

Climographs provide a good sense of a location's seasonal climate.Climate graphs are used to illustrate the average temperature and rainfall experienced at a particular place over the course of a year. ... Some graphs show both the average daily high and low temperatures for each month.

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2 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints

zzz [600]

Answer:

y= -7/2x-26/2 or y= -7/2x-13

Explanation:

To solve this question you need all of these formulas:

gradient: $\frac{y2-y1}{x2-x1}$ , Point-Slope $y-y1=m(x-x1)$ ,

perpendicular m $(m1)x(m2)=-1$ , Midpoint $(\frac{x1+x2}{2}$ , $\frac{y1+y2}{2} )$

and equation of a line $y=mx+c$

where m stands for gradient

First things first.

To start you have to know the data of the line that includes the two endpoints, so you calculate its gradient (m) of this line with the gradient fromula: $m=\frac{-4-(-8)}{5-(-9)}$ , which equals 4/14 or 2/7

(It can also be called rise/run) (Remember the rule of signs where - and - equal +)

with that information you can proceed with the point-slope or point-gradient formula, so you plug the values: y-(-8) = 2/7 (x-(-9)), which results in y+8=2/7(x+9) and then y+8=2/7x+18/7.

To finish the equation you move eight to the other side. To simplify things you can change it into a fraction as I did, and remember to change signs.

y=2/7x+18/7 -8 -> y=2/7x+18/7-56/7 . This gives us the number of y=2/7x-38/7, which is the equation of the first line.

Now to know the gradient of the second line you apply the formula of perpendicular bisector where m1 x m2 = -1. We know m1 (gradient of the first line) is 2/7, so m2 = $\frac{-1}{2/7}$ = -7/2. m2 is therefore -7/2

Now you have to know the midpoint between the two endpoints, which will act as the start point of the perpendicular bisector

M (midpoint) = $(\frac{-9+5}{2} ,$ $\frac{8+(-4)}{2} )$ , which give us the coordinates of (-2, -6)

(remember, x coordinate is always first)

with this point we can apply again the point-slope formula to know the equation of the line:

y-(-6)=-7/2(x-(-2)) -> y+6=-7/2(x+2) -> y+6=-7/2x - 14/2

Move the 6 to isolate the y

y=-7/2x -14/2 - 12/2

which equals y= -7/2x -26/2

You can check the results in this page: GraphPlotter

https://www.transum.org/Maths/Activity/Graph/Desmos.asp

To make sure the answer is correct.

Hope it helps :)

8 0

2 years ago