Move the decimal behind the first number(1) then count how many spaces you moved and that is your power. 1.304×10^7
The position of the particle as function of time is given as

The velocity as function of time is

A graph of f(t) versus t and of v(t) versus t is shown below.
The velocity increases in the intervals t = (2, 6) and t = (10, 14) and with a periodicity of 8.
In the range t = [0, 16], the velocity increases in the interval t = (2,6)∪(10, 14).
Answer: (2,6)∪(10,14)
Answer:
-12m-6n
Step-by-step explanation:
Let's break this down systematically
Start:
8m + 2n - 4(5m - 2n)
Use the distributive property
8m + 2n - <u>4(5m - 2n)</u>
8m + 2n - 20m - 8n
Match like terms <em>m </em>and <em>n</em>
8m - 20m = -12m
2n - 8n = -6n
<u>-12m-6n</u>