Someone help pls!!!!!!!!!!!

Mathematics

1 answer:

Gemiola [76]3 years ago

7 0

The answer is no question for you lol

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Ron has a bag containing 3 green pears and 4 red pears he randomly selects a lead then randomly selects another pear without rep

Alborosie

First pear    Second pear probability

green (3/7)---------green (2/6)    (3/7)*(2/6) = 1/7
      ---------red (4/6)    (3/7) *(4/6) = 2/7

red (4/7)-------------green (3/6) (4/7)*(3/6) = 2/7
   -------------red (3/6)    (4/7)*(3/6) = 2/7
   -------------------------
   1/7 + 2/7 + 2/7 + 2/7 = 1

The probailities that two are green are: 1/7

The probabilities that one is green and the other is red are:2 /7 + 2/7 = 4/7

The probabilities that two are red are: 2/7

7 0

3 years ago

What is the first step in solving this equation? 10d - 4 = 91

Vikentia [17]

Answer:

Step-by-step explanation:

the first step in solving this equation is adding 4 on both sides

10d = 95

d = 95/10 = 9.5

8 0

3 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$