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expeople1 [14]
3 years ago
11

Another bowler, Ryan Shafer, has a mean absolute deviation of 5. Based on the mean absolute deviation of Norm Duke, who has been

the more consistent bowler?
Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

Ryan is a more consistent performer

Step-by-step explanation:

The complete question is

HEL 1. Shown are the final scores for Norm Duke in the past eight bowling tournaments.

299, 281, 285, 269, 280, 269, 286, 287

Part A: What is the mean absolute deviation of Norm Duke’s scores?

A.

7.50

B.

7.00

C.

7.25

D.

6.75

Part B: Based on the mean absolute deviation from Part A, who has been the more consistent bowler if Ryan Shafer has a mean absolute deviation of 7?

Solution

First we will find the mean deviation of Duke is 7.5

The standard deviation of Ryan is 7.0. This means that the average variation in case of Duke is higher than that of average variation of Ryan.

Hence, Ryan has been more consistent performer

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A fruit juice company includes 1.872 ounces of orange juice in a 6.65-ounce bottle of a mixed fruit
BigorU [14]

Answer:

4.778 ounces

Step-by-step explanation:

Given that:

Ounces of orange juice in mixed fruit juice = 1.872

Ounces of mixed fruit juice = 6.65 ounces

Ounces of Mixed fruit juice that is not orange juice :

(Ounces of mixed fruit juice - Ounces of orange juice)

(6.65 - 1.872) ounces

= 4.778 ounces

6 0
3 years ago
Please help I really do not understand its turned in today. I WILL GIVE BRAINLIEST :)
8090 [49]

Answer:

Total area of new carpeting installed: 368

Step-by-step explanation:

What I did is too complicated to write down, so I'll just show you the math:

(12 * 8) * 2 (The area of the bedrooms)

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6 0
3 years ago
A store sells 6 bananas for $4. Determine how much it would cost to buy 15 bananas
Archy [21]

Answer:

$10

Step-by-step explanation:

Since 6 cost four dollars 3 would cost 2 dollars multiply 3 to get 15 bananas and 2 to get $10

8 0
3 years ago
Read 2 more answers
Suppose you have two six-sided dice where each side is equally likely to land face up when rolled.
nikitadnepr [17]

Answer:a. ii.

A. Is Theoretical because there is no real way of knowing what you will roll.

5 0
4 years ago
Read 2 more answers
Please answer! I crossed out the ones you don’t have to complete.
Nina [5.8K]

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

a.a as a^{1+1}=a^2

b.b.b.b as: b^{1+1+1+1}=b^4

So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

4 0
3 years ago
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