Performing the indicated multiplication on the left side gives you:
8x-24=8x-24,
8x=8x
1=1
These expressions are true for any real value of x and thus has infinitely many solutions...
It would be 2(x+3)(x+1)=0
Explanation:
I used factor by grouping. You multiply the first term (2) by the last term (6). This gives you 12 then take the factors of 12 that add up to the middle term 8. You get 6 and 2.
It should look like 2x^2+6x+2x+6=0
when you do factor by grouping you factor the first two terms and then the last two terms separately. So you get (2x+2) and (x+3). (2x+2) could be factored into 2(x+1). Then you put everything together and get 2(x+3)(x+1)=0
3-5w+12+2w-3
(3+12-3)=12
(-5w+2w)=-3w
-3w+12
