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2 years ago

Between which two integers does square root of /10 lie?

Mathematics

2 answers:

Lerok [7]2 years ago

6 0

Answer:

It is lie

Step-by-step explanation:

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Oduvanchick [21]2 years ago

6 0

Answer:

Between 3 and 4.

Step-by-step explanation:

Due to the square root of 10 being around 3.16, the value is between 3 and 4.

However, we can also find this by saying the closest two integers to the square root of 10 are 3 and 4 due to 3^3 = 9 and 4^2 = 16 and 10 being between those two values.

Hope this helped!

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Parallelogram ABCD is a rectangle.

svp [43]

Y = 3 because in a rectangle, the diagonals are ALWAYS congruent. so you would have:
5y - 2 = 4y + 1
-4y+2 -4y + 2
y = 3

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3 years ago

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Mars2501 [29]

Answer:

22,-15 ................ maybe

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2 years ago

The population of Chicago, Illinois, in 2003 was 2,869,121. The area of Chicago was 227.1 square miles. What was the average num

ValentinkaMS [17]

Answer:

12,633.7

Step-by-step explanation:

population of Chicago, in 2003 = 2,869,121

The area of Chicago = 227.1 square miles.

What was the average number of people living in 1 square mile?

Average number of people living in 1 square mile also refers to the population density of Chicago

Average number of people living in 1 square mile = Total population / total square miles

= 2,869,121 / 227.1

= 12633.734037868

Approximately

12,633.7

5 0

2 years ago

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

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2 years ago

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Natasha2012 [34]

Answer:

1) 3x²+8x

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2 years ago