Answer:
37
Step-by-step explanation:
The first thing is to calculate critical z factor
the alpha and the critical z score for a confidence level of 90% is calculated as follows:
two sided alpha = (100% - 90%) / 200 = 0.05
critical z factor for two sided alpha of .05 is calculated as follows:
critical z factor = z factor for (1 - .05) = z factor for (.95) which through the attached graph becomes:
critical z factor = 2.58
Now we have the following formula:
ME = z * (sd / sqrt (N) ^ (1/2))
where ME is the margin of error and is equal to 6, sd is the standard deviation which is 14 and the value of z is 2.58
N the sample size and we want to know it, replacing:
6 = 2.58 * (14 / (N) ^ (1/2))
solving for N we have:
N = (2.58 * 14/6) ^ 2
N = 36.24
Which means that the sample size was 37.
Answer:
x = 4
Step-by-step explanation:
Solution:
-3(4x + 3) + 4(6x + 1) = 43
-12x - 9 + 24x + 4 = 43
12x - 5 = 43
12x = 43 + 5
12x = 48
x = 48 / 12
Therefore, x = 4
PLEASE MARK ME AS BRAINLIEST!!!
Answer:
0.775
Step-by-step explanation:
Divide 3.10 by the number of cans you have. The total number of cans you have is 4. So divide 3.10 by 4 and you will have the answer of 0.775.
Answer:
a) S = {1, 2, 3}
b) P(odd number) = 
c) No
d) Yes
Step-by-step explanation:
a) The sample space is the set of all possible outcomes. By definition, the elements of a set should not be repeated. Hence, the sample space S = {1, 2, 3}
However, the sample is not equiprobable because each element has different probabilities.
b) P(odd number) = 
Note that the odd numbers are 1 (on three faces) and 3 (on one face).
c) The fact the die has been biased does not change the possible outcomes. It only changes the probability of getting any given number.
d) Because the 3-face has been loaded, this probability changes. In fact, it is calculated thus:
Let's assume the probability for 1 or 2 is 
. Then that of 3 is 
(because it is twice the others). The sum of probabilities must be 1.
P(odd number) = 
Prob(1) + Prob(3)
= 
= 
