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n200080 [17]
2 years ago
12

Is 7^2 greater then or less than 3^4?​

Mathematics
2 answers:
nevsk [136]2 years ago
7 0
<h2>Answer: <em><u>Less Than</u></em></h2>

Step-by-step explanation: 7^2 = 49, but 3^4 = 81. 49 < 81

sveta [45]2 years ago
4 0

Answer: less

Step-by-step explanation: 7^2 is 49 and 3^4 is 81....

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N76 [4]

Answer:

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Step-by-step explanation:

 

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2 years ago
Choose the quadrilateral that is not a rhombus of congruent sides and two angle that each measure 120 degrees
Amanda [17]

Answer for the above question is <u>option C</u>

<u>Step-by-step explanation:</u>

<u>Option C -</u>  It's a quadrilateral but not a rhombus . As we know rhombus has congruent sides while its two angle can't be measured 120 degrees but in option C it seems two vertically opposite angles of to be 120 degrees. In rhombus opposite angles are same while adjacent angles are supplementary. All options except C are the rhombus of congruent sides.

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3 years ago
Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

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Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

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All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

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7 0
3 years ago
NEED HELP ASAP!<br> find the volume of the cylinder
denpristay [2]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
What’s the error and how can I correct it number 24.
Aloiza [94]

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4 0
3 years ago
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