The answer is 5 3/4.............
Answer:
Step-by-step explanation:
Let's say that the time it took him to get to work in the morning is t hours. Then the time it took him to get home in the afternoon must be 1 - t hours. We know that for any trip, distance equals rate times time or d = rt . That means that the distance he drove to work is given by , but we also know that the distance he drove to get home must be the same distance, because he took the same route (and, presumably, no one picked up him house and moved it while he was at work) so for the trip home we can say d = 30 × (1 - t) and since the distances are equal, we can say:
45t = 30 × (1 - t)
45t = 30 - 30t
45t + 30t = 30
75t = 30
t = 30/75
t = 2 /5 hour to drive to work at 45mph
Since , d = rt
d = 45 ×(2/5) = 18miles
Answer:
130
Step-by-step explanation:
From the FIQURE of the question, we can see that line "e" is parallel to line "f" then we can say (2x + 18)=( 4x - 14)
Then we can collect like terms
2x-4x= -14-18
-2x=-32
The negatives cancelled out we have
x = 16
From the question, At the intersection of lines b and f, the top right angle is (4 x minus 14) degrees
Angle on a straight line is 180° then we can calculate "y" as
y = 180 - (4x - 14)
= 180-4x+14
= 180+14-4x
But x= 16, then substitute we have
= 180 +14 - 14(16)
= 130
Hence, the value of y is 130
CHECK THE ATTACHMENT FOR THE FIQURE
Answer:
Option (B) a 95% confidence interval does not include the hypothesized value of the parameter
Step-by-step explanation:
Alpha, α = 0.05
We conduct a hypothesis test at 5% significance level.
The null hypothesis will be rejected when
Option (B) a 95% confidence interval does not include the hypothesized value of the parameter
- When a 95% confidence interval is constructed,it contains all the possible values for the parameter being estimated.
- If the value of the parameter stated in the null hypothesis is contained in the 95% confidence interval, then we fail to reject the null hypothesis 0.05 level and accept it.
- If the value stated in the null hypothesis is not in the interval, then we fail to accept the null hypothesis and reject the null hypothesis at the 0.05 level.
