Answer:
-13, -3
15, 2.6
Step-by-step explanation:
x, y are the numbers
x = 5y + 2
x×y = 39
(5y + 2)×y = 39
5y² + 2y - 39 = 0
the solution of a quadratic equation :
y = (-b ± sqrt(b² - 4ac))/2a
a = 5
b = 2
c = -39
y = (-2 ± sqrt(2² - 4×5×-39))/2×5 =
= (-2 ± sqrt(4 + 780))/10 =
= (-2 ± sqrt(784))/10 = (-2 ± 28)/10
y1 = (-2 + 28)/10 = 26/10 = 2.6
y2 = (-2 - 28)/10 = -30/10 = -3
x1 = 5×2.6 + 2 = 13 + 2 = 15
x2 = 5×-3 + 2 = -15 + 2 = -13
First, square both sides. This will cancel out the radical.
(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
Gradient is the slope, which is the letter m in the equation.
The point is written as (x1, y1) so replace x1 and y1 in the equation with the numbers in the given point.
A would be y - 1= 2(x-4)
B: y +5 = 5(x-2)
C: y-1= -3(x+1)
D: y -6 = 1/2(x-1)
E: y +1/4 = -2(x-3:4)
F: y+7 = -1/5(x+ 3)
7.8456 x 10^(-4)
this means you move the decimal place to the left 4 places to get the actual value
Answer:this is not an equation
Step-by-step explanation:
