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mihalych1998 [28]
3 years ago
14

You need to use 4/5 cups of strawberries for a single pie how many cups are needed for 2 pies i know the answer is 13/5 but how

do you work that out
Mathematics
2 answers:
WINSTONCH [101]3 years ago
7 0

Answer:

8

Step-by-step explanation:

Rina8888 [55]3 years ago
7 0
The answer is 8/5
Because a pie contains a 4/5 cup of strawberries you can just add the two amounts
4+4/5 =8/5
Or you can multiply the 4/5 with two
4/5 x 2/1 —> (4x2)/(5x1) =8/5
Hope this helped
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ASAP h(t)=-5t^2+5t+10<br><br> Please help me find roots and roots equation
Alex

Answer:

t = -1, 2

Step-by-step explanation:

Step 1: Define

h(t) = -5t² + 5t + 10

Step 2: Factor

h(t) = -5(t² - t - 2)

h(t) = -5(t - 2)(t + 1)

Step 3: Find roots

0 = -5(t - 2)(t + 1)

0 = (t - 2)(t + 1)

t - 2 = 0

t = 2

t + 1 = 0

t = -1

8 0
3 years ago
The population of pine bluff is 6791 and is decreasing at a rate of 7 per year.Write the linear equation that models this situat
Anna11 [10]

Answer:

y= 6971 -7 x  OR y = -7x + 6971

Step-by-step explanation:

the 6971 is the original number you started with, you are now decreasing by 7, so you use the value of -7. The x is the number of years that pass by, so the variable x affects the number 7 because it says decreases by 7 per year. The x does not go with 6971 as that number doesn't get directly affected.

3 0
4 years ago
Read 2 more answers
Hey there! posted picture of question help please
kakasveta [241]
For this case we have the following function:
 f (x) = (1/3) * (4 ^ x)
 We must evaluate the function for x = 2
 We have then:
 f (2) = (1/3) * (4 ^ 2)
 Rewriting:
 f (2) = (1/3) * (16)
 f (2) = 16/3
 Answer:
 
The function evaluated at x = 2 is:
 
f (2) = 16/3
 
option A
7 0
3 years ago
PLEASE HELP ASAP!! <br> Please its due in 5 min!
-Dominant- [34]
Answer:

first question) m = - 63
second question) y = 4

sorry if this is late, hope this helped!
5 0
2 years ago
Factor 7(x − 3)2 − 4(x − 3) − 3 completely.
Nezavi [6.7K]
7(x-3)^2-4(x-3)-3\\\\substitute\ t=x-3,\ then\ we\ have\\\\7t^2-4t-3\\\\a=7;\ b=-4;\ c=-3\\\\\Delta=b^2-4ac\\\\\Delta=(-4)^2-4\cdot7\cdot(-3)=16+84=100\\\\t_1=\dfrac{-b-\sqrt\Delta}{2a};\ t_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\t_1=\dfrac{-(-4)-10}{2\cdot7}=\dfrac{4-10}{14}=\dfrac{-6}{14}=-\dfrac{3}{7}\\\\t_2=\dfrac{-(-4)+10}{2\cdot7}=\dfrac{4+10}{14}=\dfrac{14}{14}=1\\\\7t^2-4t-3=7\left(t+\dfrac{3}{7}\right)(t-1)=(7t+3)(t-1)\\\\=(7(x-3)+3)(x-3-1)=(7x-21+3)(x-4)\\\\=\boxed{(7x-18)(x-4)}
7 0
4 years ago
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