Answer:
Probability at least one car will get punctured: 0.39347
Step-by-step explanation:
B(10,000 , 0.00005)
P(X ≥ 1) = 1 - P(X = 0)
= 1 - (1 - 0.00005)^10,000
= 1 - (0.99995)^10,000
= 1 - 0.60652...
= 0.39347 (probability that at least one car will get punctured)
As you can tell P(X ≥ 1) as we have to solve for the probability that at least one car will get punctured. That is of course 1 - [ P(X = 0) ].
The answer is B) <span>(q - 2)(2p - 5r)
</span>2pq - 5qr + 10r - 4p = 2pq - 4p - 5qr + 10r
= 2pq - 4p - (5qr - 10r)
= 2p(q - 2) - 5r(q - 2)
= (q - 2)(2p - 5r)
I will solve you system by substitution
y = 2x - 3 ; x + y = 1
→Step 1: Solve y = 2x - 3 for y
→Step 2: Substitute 2x - 3 for y in x + y = 1:
x + y = 1
x + 2x- 3 = 1
3x - 3 = 1 (Simplify both sides of the equation)
3x - 3 + 3 = 1 + 3 (Add 3 both sides)
3x = 4
3x ÷ 3 = 4 ÷ 3 (Divide each side by 3)
x = 4/3
→Step 3: Substitute 4/3 for x in y = 2x - 3:
y = 2x - 3
y = 2 (4/3) -3
y = -1/3 (Simplify both sides of the equation)
Answer:
x = 4/3 and y = -1/3
∫Hope that helps∫
Answer: 288/18+7x5
Step-by-step explanation:
Hey!
If 112 people are getting cake and 5/8 are getting chocolate, that means the remaining will get chocolate.
8/8 - 5/8 = 3/8
3/8 are getting chocolate. You have to find 3/8 of 112.
3/8 × 112 = 336/8 = 42
42 people are getting carrot cake
:)
