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bonufazy [111]
2 years ago
9

Find the length of a square whose diagonal is 15cm​

Mathematics
1 answer:
Vladimir [108]2 years ago
4 0
2a^2 = 225
So a^2 = 225/2
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Differentiate Square numbers and cube numbers
pashok25 [27]

Answer:

square numbers are numbers raised up to the power of two in essence the number multiplied by it self

6 0
3 years ago
If f(x) = 3x-1 and g(x)= x+2 find (f-g)(x)​
wariber [46]

Answer:

2x-3

Step-by-step explanation:

f(x) = 3x-1

g(x) = x+2

Find (f-g)(x), this means we need to subtract g from x.

(3x-1) - (x+2)

Subtract the like terms:

3x -x = 2x

-1 -2 = -3

Combine them to get 2x-3

7 0
3 years ago
Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.
SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at (0,1).

The graph has an x-intercept at (-7,0).

Step-by-step explanation:

Given: The graph is y=\sqrt[3]{x-1}+2

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of (-\infty, \infty).

To find the y-intercept:  To find the y-intercept, substitute x=0 in y=\sqrt[3]{x-1}+2.

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}

Thus, the y-intercept is (0,1)

To find the x-intercept: To find the x-intercept, substitute y=0 in y=\sqrt[3]{x-1}+2 .

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}

Thus, the x-intercept is (-7,0)

8 0
2 years ago
Read 2 more answers
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eimsori [14]

Answer:

{\boxed{ \fbox{ \fbox{ \fbox{ \red{hello}}}}}}

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5 0
3 years ago
27 ÷ 31 = 0.870967742<br><br> I need the answer simplified.
Neko [114]
To simplify most teachers prefer to round to tenth or hundreth
best answers: 0.9, 0.87
7 0
3 years ago
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