OK, I will try my best to help you out, young lad. Just kidding, I am young too!
OK, so first you have to assign variables.
Let's make the first number = x-5
the second number is =x
Now, set up an equation
4(x-5)+5(x)=74
Use the distributive property to simplify the equation.
4x-20+5x=74
simplify the problem to find x
9x-20=74
9x=94
x=10.4 or 94/9
Now, apply the answer..
We know that the second number, x = 10.4 ( or 94/9), so the larger number is...
94/9 - 5= 49/4 of 5.4
so the answers are
first number= 5.4 (fraction form- 49/4)
second number= 10.4 (94/9)
Answer:
It is very difficult to know because you did not include the function g(x), you only gave us f(x).
Given two lists of ordered pairs [x,f(x)] and [x,g(x)]. If for every ordered pair on the f(x) list the reverse is on the g(x) list the functions are inverses.
f(0) = 5 so for (0,5) on the f(x) list then (5,0) must be on the g(x) list
f(1) = 7 so for (1,7) on the f(x) list then (7,1) must be on the g(x) list
f(2) = 9 so for (2,9) on the f(x) list then (9,2) must be on the g(x) list
So even though you didn’t list g(x), g(x) = (x/2) - 5/2
Answer:
Therefore,
Volume of the cylinder is 24501.42 m³.
Step-by-step explanation:
Given:
Height of Cylinder = 27 m
Diameter, d = 34 m
![Radius = \dfrac{d}{2}=\dfrac{34}{2}=17\ m](https://tex.z-dn.net/?f=Radius%20%3D%20%5Cdfrac%7Bd%7D%7B2%7D%3D%5Cdfrac%7B34%7D%7B2%7D%3D17%5C%20m)
Volume of a Cylinder = ?
Solution:
We know that
![\textrm{Volume of a Cylinder}=\pi (Radius)^{2}\times Height](https://tex.z-dn.net/?f=%5Ctextrm%7BVolume%20of%20a%20Cylinder%7D%3D%5Cpi%20%28Radius%29%5E%7B2%7D%5Ctimes%20Height)
Substituting the given values in formula we get
![\textrm{Volume of a Cylinder}=3.14 (17)^{2}\times 27=24501.42\ m^{3}](https://tex.z-dn.net/?f=%5Ctextrm%7BVolume%20of%20a%20Cylinder%7D%3D3.14%20%2817%29%5E%7B2%7D%5Ctimes%2027%3D24501.42%5C%20m%5E%7B3%7D)
Therefore,
Volume of the cylinder is 24501.42 m³.
<span>ƒ(x) = –x^2 + 1 for x = –3.
Substitute x for -3
</span><span>ƒ(x) = –( -3)^ 2 + 1
</span>ƒ(x) = -9 + 1
ƒ(x) = -8<span>
</span>