Food A contains 150 calories in 3/4of a serving. Food B contains

2 answers:

8 0

Food A has fewer calories per serving.

I found this by taking the first food (A) and dividing 150 by 3. This gave me 50, which I added onto 150 to give me my 4/4 of a serving (200 calories).

With food B, I did the same process. I took 250/2 and added that to the original amount to get the final third of the serving, which resulted in food B being 375 calories.

Pavlova-9 [17]2 years ago

6 0

There are 375 calories per serving

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Help me solve this problem please

miss Akunina [59]

Answer:

JL = 54

Step-by-step explanation:

JL = JK + KL

JK = KL

8x+11 =14x-1

12 = 6x

x = 2

substitute for x:

8(2)+11 + 14(2)-1 = JL

JL = 16+11+28-1

JL = 54

7 0

2 years ago

The sum of three consecutive even integers is -78, what are the integers ?

Digiron [165]

First, you need to analize and understand the problem, then you must choose and strategy. There is a wide variety of strategies to solve a mathematical problem, in this case, you can use the following, which is based on the information given above:
1. You have that the sum of three consecutive even integers is $-78$ , therefore, you can given the variable $x
$ to the first integer, the second even integer is $x+2$ and the third one is $x+4
$ .
2. Calculate x:
 $x+(x+2)+(x+4)=-78$ 
 $3x+6=-78$
 $x=-28
$ 
 $x+2=-28+2=-26
$ 
 $x+4=-28+4=-24
$ 
Therefore, the answer is: $-28,-26,-24
$