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Contact [7]
3 years ago
6

Food A contains 150 calories in 3/4of a serving. Food B contains

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0
Food A has fewer calories per serving.

I found this by taking the first food (A) and dividing 150 by 3. This gave me 50, which I added onto 150 to give me my 4/4 of a serving (200 calories).

With food B, I did the same process. I took 250/2 and added that to the original amount to get the final third of the serving, which resulted in food B being 375 calories.
Pavlova-9 [17]3 years ago
6 0
There are 375 calories per serving
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Can we conclude that these two triangles are congruent?
Aleonysh [2.5K]

Answer:

Yes,

Step-by-step explanation:

because two sides are shown equal to each other, a and b. Also two angles are equal to each other, x and y. Once you know two angles or two sides are equal so is the third side.

Another way is SAS (side angle side). There is side a, angle y, and side b. These are shown on both triangles.

Therefore, we can conclude these two triangles are congruent.

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4 years ago
Write a multiplication sentence that shows the zero property of multiplication. Explain why it shows this property.
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3 years ago
Find the equation in slope-intercept form that describes a line through (–1, 1) and (2, 3)
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  y = 2/3x + 5/3

Step-by-step explanation:

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a rectangle has a height of n3+4n2+3n and a width of n^3+5n^2 express the area of the entire rectangle
alukav5142 [94]

<u>Given</u>:

It is given that the height of the rectangle is n^3+4n^2+3n

The width of the rectangle is n^3+5n^2

We need to determine the area of the entire rectangle.

<u>Area of the rectangle:</u>

The area of the rectangle can be determined using the formula,

A=height \times width

Substituting the values, we have;

A=(n^3+4n^2+3n)(n^3+5n^2)

Multiplying each term within the parenthesis, we get;

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Simplifying, we get;

A=n^{6}+5 n^{5}+4n^{5}+20 n^{4}+3  n^{4}+15 n^{3}

Adding the like terms, we have;

A=n^{6}+9n^{5}+23 n^{4}+15 n^{3}

Thus, the area of the entire rectangle is n^{6}+9 n^{5}+23 n^{4}+15 n^{3}

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