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Tresset [83]
3 years ago
6

List the sequence of transformations that must occur to transform rectangle ABCD into A'B'C'D

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

Rectangle ABCD was dilated by \frac{1}{2} followed by a translation of 7 units right and 1 unit down.

Step-by-step explanation:

Rectangle A'B'C'D' is a dilated form of rectangle ABCD.

Followed by a translation, as shown in the figure attached.

For dilation,

Scale factor = \frac{\text{Side length of image}}{\text{Side length of original}}

                    = \frac{2}{4}

                    = \frac{1}{2}

Therefore, rectangle ABCD was dilated with a scale factor of \frac{1}{2} about the origin.

Coordinates of point A → (-10, 6)

Coordinates of point A' → (1, 2)

Coordinates of image of point A after dilation,

(x, y) → (kx, ky)

A(-10, 6) → A"(-5, 3)

Coordinates of point A" after translation of 'h' units to the right and 'k' units down.

(x, y) → (x + h, y - k)

A"(-5, 3) → A'[(-5 + h), (3 - k)]

By comparing the coordinates of A'[(1, 2) and (-5 + h, 3 - k)],

-5 + h = 2 ⇒ h = 7

3 - k = 2 ⇒ k = 1

Therefore, rectangle ABCD was dilated by \frac{1}{2} followed by a translation of 7 units right and 1 unit down.    

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Tpy6a [65]

Since segments ST and PQ are parallel, triangles SRT and PRQ are similar due to the AAA postulate. In general, the ratio between the corresponding sides of two similar triangles is constant; therefore,

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Furthermore,

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Then,

\frac{12}{PR}=\frac{TS}{15}\begin{gathered} \Rightarrow\frac{12}{PR}=\frac{4+PS}{15} \\ \Rightarrow\frac{12}{PS+12}=\frac{4+PS}{15} \end{gathered}

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Solve the quadratic equation in terms of PS, as shown below

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Hence, the answer is PS=6

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Answer:

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Step-by-step explanation:

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