Answer:

Step-by-step explanation:
3 envelopes having 2 red card
2 envelopes having 1 red card and 1 black card
1 envelope having 2 black cards
We are given that . An envelope is selected at random and a card is withdrawn and found to be red.
So, No. of ways of envelope having red card = 3+2 = 5
No. of required ways of envelope having 1 red card and 1 black card = 2
So, probability of getting an envelope having 1 red card and 1 black card = 
Hence The chance the other card is black is 
Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.
The people are chosen from the sample without replacement, which is why the <u>hypergeometric distribution</u> is used to solve this question.
Hypergeometric distribution:
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- 1000 people means that

- 130 can wiggle their ears, thus

- Two are selected, thus
.
The probability that neither can wiggle his or her ears is P(X = 0), thus:


0.7568 = 75.68% probability that neither can wiggle his or her ears.
A similar problem is given at brainly.com/question/24826394
Vas happenin!!
19. TX
20. O and I can’t see the other bottom of the cube
21. WS
Hope this helps *smiles*
Sorry if it’s wrong
We have given the table of number of male and female contestants who did and did not win prize
The probability that a randomly selected contestant won prize given that contestant was female is
P(contestant won prize / Contestant was female)
Here we will use conditional probability formula
P(A/B) = 
Let Event A = selected contestant won prize and
event B = selected contestant is famale
Then numerator entity will
P(A and B) = P(Contestant won prize and Contestant is female)
= Number of female contestant who won prize / Total number of contestant
= 3 /(4+9+3+10)
= 3 / 26
P(A and B) = 0.1153
P(B) = P(contestant is female )
= Number of female contestant / Total number of contestants
= (3+10) / 26
P(B) = 0.5
Now P(A / B) = 
= 0.1153 / 0.5
P(A / B) = 0.2306
The probability that randomly selected contestant won prize given that contestant is female is 0.2306
Converting probability into percentage 23.06%
The percentage that randomly selected contestant won prize given that contestant is female is 23%
J stands for Jon, A stands for Angelica, and C stands for Chaya.
J = C - 3
A = C + 4
C = A - 4
= 196 h
62 + 65 + 69 = 196
Jon worked 62 hours, Chaya worked 65 hours, and Angelica worked 69 hours.
And that's your answer! ^ I hope this helped you! c: