Answer:
2,1
Step-by-step explanation:
Answer:
I believe it's A
Step-by-step explanation:
Hope this helps!
The correct answer is option c bro.
Answer:
The correct answer is the last one. It is the only equation with a negative slope. The slope in the picture is negative and therefore it is the only possible answer.
Answer:
1.41
Step-by-step explanation:
<em>The maximum walking speed S, in feet per second, of an animal can be modeled by the equation S= √(gL), where g = 32ft/sec² and L is the length, in feet, of the animal's leg. To the nearest hundredth, how many times greater is the maximum walking speed of a giraffe with a leg of 6 feet than a hippopotamus with a leg of 3 feet?</em>
<em />
Step 1: Calculate the maximum walking speed of a giraffe
The leg of a giraffe measures L = 6 ft.
Sg= √(g × Lg)
Sg= √(32 ft/s² × 6 ft) = 13.86 ft/s
Step 2: Calculate the maximum walking speed of a hippopotamus
The leg of a hippopotamus measures L = 3 ft.
Sh= √(g × Lh)
Sh= √(32 ft/s² × 3 ft) = 9.80 ft/s
Step 3: Determine how many times greater is the maximum walking speed of a giraffe than a hippopotamus
We will make the ratio Sg/Sh
Sg/Sh = (13.86 ft/s)/(9.80 ft/s) = 1.41
