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3 years ago

Discuss five processes for analyzing a qualitative study

Computers and Technology

2 answers:

dusya [7]3 years ago

6 0

Answer:

Prepare and organize your data. Print out your transcripts, gather your notes, documents, or other materials.

Review and explore the data.

Create initial codes.

Review those codes and revise or combine into themes.

Present themes in a cohesive manner.

xxMikexx [17]3 years ago

4 0

1. Prepare and organize your data.

Print out your transcripts, gather your notes, documents, or other materials. Mark the source, any demographics you may have collected, or any other information that will help you analyze your data.

2. Review and explore the data.

This will require you to read your data, probably several times, to get a sense of what it contains. You may want to keep notes about your thoughts, ideas, or any questions you have.

3. Create initial codes.

Use highlighters, notes in the margins, sticky pads, concept maps, or anything else that helps you to connect with your data. See the attached document that demonstrates how one might highlight key words and phrases as well as make notes in the margins to categorize the data:

4. Review those codes and revise or combine into themes.

Identify recurring themes, language, opinions, and beliefs.

5. Present themes in a cohesive manner.

Consider your audience, the purpose of the study, and what content should be included to best tell the story of your data.

Hope this helped you!!!

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Lacking in movement, action, or change, especially in a way viewed as undesirable or uninteresting�

Elenna [48]

Answer:

Static

Explanation:

I just took the test man!

5 0

3 years ago

Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, a

kkurt [141]

Answer:

(a) Calculate the average CPI for each machine, M1, and M2

Average CPI = Cycles per Instruction * Frequency of each Instruction

= CPI * F

For Machine M1:

Cycles per Instruction/ Clocks per Instruction = (60%)* 1 + (30%)*2 + (10%)*4

= (0.60) * 1 + (0.30) * 2 + (0.10) * 4

= 0.6 + 0.6 + 0.4

= 1.6

For Machine M2:

Cycles per Instruction/ Clocks per Instruction= (60%)*2 + (30%)*3 + (10%)*4

= (0.60) *2 + (0.30) * 3 + (0.10) *4

= 1.2 + 0.9 + 0.4

= 2.5

(b) Calculate the average MIPS ratings for each machine, M1 and M2.

MIPS rating can be found by using this formula

MIPS rating = Instruction Count / Execution Time * 10^6

= Instruction count / IC X CPI * Clock cycle time * 10^6

= IC X Clock rate / IC X CPI X 10^6

= Clock Rate/(CPI * 10^6)

MIPS rating for Machine M1:

The clock rate for M1 is 80 MHz and CPI calculated in (a) is 1.6 So:

MIPS rating = (80 * 10^6) / (1.6 * 10^6 )

= 80000000/ 1600000

= 50

MIPS rating for Machine M2:

The clock rate for M1 is 100 MHz and CPI calculated in (a) is 2.5 So:

MIPS rating = (100 * 10^6 ) / (2.5 * 10^6 )

= 100000000 / 2500000

= 40

(c) Which machine has a smaller MIPS rating?

M2 has a smaller MIPS rating which is 40.

Which individual instruction class CPI do you need to change, and by how much, to have this machine have the same or better performance as the machine with the higher MIPS rating.

Machine M1 has the higher MIPS rating than M2 and in order to make M2 perform better than M1, the CPI of instruction class A should be modified. Lets change the instruction class A CPI to 1 in place of 2.

Then:

Cycles per Instruction/ Clocks per Instruction= (60%)*1 + (30%)*3 + (10%)*4

= (0.60 * 1) + (0.30 * 3) + (0.10 * 4)

= 0.60 + 0.9 + 0.4

= 1.9

Average MIPS rating = (100 * 10^6) / (1.9 * 10^6 )

= 100000000 / 1900000

= 52.6

Average MIPS rating is of M2 after changing instruction class A CPI is 52.6 which is better than the average MIPS rating of M1 which is 50.0

4 0

3 years ago

What is web <br>searching engine ?

Nikolay [14]

A Web search engine is a specialized computer server that searches for information on the Web. The search results of a user query are often returned as a list. The hits may consist of web pages, images, and other types of files.

4 0

3 years ago

You connect three 0.5 volt lights in series. Each light has a resistance of 25ohms. Answer the following.

viktelen [127]

1. 3 times the light voltage, ie., 3*0.5 = 1.5V
2. Total R = 3*25 = 75Ω, V=1.5V, I = V/R = 1.5/75 = 20 mA
3. A 1.5V battery (e.g., an AA battery) with a charge of at least 20mAh. AA batteries should be able to handle this easily.

7 0

4 years ago

Write a program which:

Studentka2010 [4]

Answer:

Ill do this in C# and Java

Explanation:

C#:

public static void Main(string[] args)

{

string input = Console.ReadLine();

switch (input)

{

case "A1":

Console.WriteLine("Footwear:");

Console.WriteLine("Shoes");

break;

case "B1":

Console.WriteLine("Tops:");

Console.WriteLine("Jackets");

break;

case "C1":

Console.WriteLine("Pants:");

Console.WriteLine("Trousers");

break;

case "A2":

Console.WriteLine("Footwear:");

Console.WriteLine("Trainers");

break;

case "B2":

Console.WriteLine("Tops:");

Console.WriteLine("TShirts");

break;

case "C2":

Console.WriteLine("Pants:");

Console.WriteLine("Shorts");

break;

default:

Console.WriteLine("Incorrect Input");

break;

}

Java:

public static void main(String[] args)

{

Scanner myObj = new Scanner(System.in); // Create a Scanner object

String input = myObj.nextLine();

{

switch (input)

{

case "A1":

System.out.println("Footwear:");

System.out.println("Shoes");

break;

case "B1":

System.out.println("Tops:");

System.out.println("Jackets");

break;

case "C1":

System.out.println("Pants:");

System.out.println("Trousers");

break;

case "A2":

System.out.println("Footwear:");

System.out.println("Trainers");

break;

case "B2":

System.out.println("Tops:");

System.out.println("TShirts");

break;

case "C2":

System.out.println("Pants:");

System.out.println("Shorts");

break;

default:

System.out.println("Incorrect Input");

break;

}

3 0

4 years ago