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3 years ago

Juan is going to make a small table with a circular top. He drew a circle with a diameter of 22 inches to

Mathematics

1 answer:

Elanso [62]3 years ago

3 0

Answer:

C. 380

Step-by-step explanation:

Area of the tabletop = area of a circle

Area of a circle = πr²

radius (r) = ½*diameter = ½*22 = 11 in

Take π as 3.14

Plug in the values into the formula

Area of tabletop = 3.14*11² = 379.94

Area of tabletop would be approximately 380 in² (to nearest whole number)

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Evaluate. (w^2/x -3) ÷10 × z when w= -4, x = 0.8, and z = -4/5 Enter your answer as a simplified mixed number in the box.

Digiron [165]

Answer:

-1.36

Step-by-step explanation:

(-4^2/0.8-3)/10×-4/5=-1.36

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2 years ago

A high school will graduate 100 students. of these, 52 students plan to attend college.

marishachu [46]

A total of 48 students will not go to college

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3 years ago

|-2| + |15| = evaluate

AVprozaik [17]

Answer:

Step-by-step explanation:

|-2|=2

|15|=15

2+15=17

6 0

3 years ago

Read 2 more answers

erik drove 439.92 miles on 15.6 gallons of gas. To the nearest hundredth, how many miles could he drive on 39.7 gallons of gas?

Thepotemich [5.8K]

In the question it is already given that Eric drove for 439.92 miles on 15.6 gallons. It is required to find the distance traveled on 39.7 gallons of gas. Also we have to find the answer to the nearest hundredth.
Then,
In 15.6 gallons Eric can drive for a distance = 439.92 miles
In 39.7 gallons Eric can drive for a distance = [(439.92/15.6) * 39.7] miles
= 1119.54 miles
So the total distance traveled by Eric is 1120 miles with 39.7 gallons of gas. The answer has been calculated to the nearest hundredth.

6 0

3 years ago

Prove that sin20sin40sin60sin80=3/16

never [62]

We'll use the following properties of sine and cosine to prove this:

$sin(a)\cdot sin(b) = \frac12(cos(a-b) - cos(a+b))$

$cos(a)\cdot cos(b) = \frac12(cos(a+b) + cos(a-b))$

$cos(180+a) = cos(180-a)$

Then it's just a matter of filling it in...

sin20sin40 * sin60sin80 = 1/2(cos20 - cos60) * 1/2 (cos20 - cos140) =

1/8( cos40 + 1 - cos160 - cos120 - cos40 - cos80 + cos80 + cos200) =

1/8(1 - cos160 - cos120 + cos200) =

1/8(1 - cos160 - cos120 + cos160) =

1/8(1 - cos120 ) = 1/8( 1 + 1/2 ) = 3/16

5 0

3 years ago