It seems that you are trying to find the length of hair of Florencia on Tuesday.
Given that length of the hair of Florencia on Monday = h centimeters
On Tuesday, she got hair cut.
So new length of the hair of Florencia on Tuesday = 75% of Monday value
= 75% of (h)
= 0.75* (h)
= 0.75h
Hence final answer is the length of the hair of Florencia on Tuesday is ( 0.75h ) centimeters.
Answer:
![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Step-by-step explanation:
x^2 + 1 = 4
x^2 = 3
![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Answer:
m= 67.5 and n=56.25
Step-by-step explanation:
180-15=165
165/2= 82.5
90-15= 75
75+75= 150
180-150=30
30+82.5= 112.5
180- 112.5= 67.5
m= 67.5
180-67.5= 112.5
112.5/2= 56.25
n= 56.25
Step-by-step explanation:
Given:
![\vec{\textbf{F}}(x, y, z) = ye^z\hat{\textbf{i}} + xe^z\hat{\textbf{j}} + xye^z\hat{\textbf{k}}](https://tex.z-dn.net/?f=%5Cvec%7B%5Ctextbf%7BF%7D%7D%28x%2C%20y%2C%20z%29%20%3D%20ye%5Ez%5Chat%7B%5Ctextbf%7Bi%7D%7D%20%2B%20xe%5Ez%5Chat%7B%5Ctextbf%7Bj%7D%7D%20%2B%20xye%5Ez%5Chat%7B%5Ctextbf%7Bk%7D%7D)
A vector field is conservative if
![\vec{\nabla}\textbf{×}\vec{\text{F}} = 0](https://tex.z-dn.net/?f=%5Cvec%7B%5Cnabla%7D%5Ctextbf%7B%C3%97%7D%5Cvec%7B%5Ctext%7BF%7D%7D%20%3D%200)
Looking at the components,
![\left(\vec{\nabla}\textbf{×}\vec{\text{F}}\right)_x = \left(\dfrac{\partial F_z}{\partial y} - \dfrac{\partial F_y}{\partial z}\right)_x](https://tex.z-dn.net/?f=%5Cleft%28%5Cvec%7B%5Cnabla%7D%5Ctextbf%7B%C3%97%7D%5Cvec%7B%5Ctext%7BF%7D%7D%5Cright%29_x%20%3D%20%5Cleft%28%5Cdfrac%7B%5Cpartial%20F_z%7D%7B%5Cpartial%20y%7D%20-%20%5Cdfrac%7B%5Cpartial%20F_y%7D%7B%5Cpartial%20z%7D%5Cright%29_x)
![= xe^z - ye^z \neq 0](https://tex.z-dn.net/?f=%3D%20xe%5Ez%20-%20ye%5Ez%20%5Cneq%200)
Since the x- component is not equal to zero, then the field is not conservative so there is no scalar potential
.
Answer:
Part A. He exercised for 1.5 hours.
60 + 30 = 1.5 hours.
Part B. Jacob spends 15 minutes doing freehand exercise.
Part C. No, because he spent 1.5 hours altogether.