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melomori [17]
3 years ago
11

Help what are the intersepts?

Mathematics
1 answer:
HACTEHA [7]3 years ago
6 0
<h2>x= 4, y=4</h2><h2 />

<u>First start solving for x to find y.</u>

Plug in y= 3/2x-2

4x-2(3/2x-2)=8

<u>Once you find x, plug in</u>

4(4)-2y=8

Hopefully the rest is self explanatory with the evidence I provided.

I hope this helped!

<h2 />

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The functions f(x) and g(x) are described below:
sesenic [268]

Suppose that the <u>function</u> f(x) is the <u>parrent</u> function and the<u> graph</u> of the function g(x)=f(x)-a can be obtained from the graph of the parrent function f(x) by <u>shifting down</u> a units.

Rewrite the expression for the function g(x) in the following way:

g(x)=32x-9=32x+8-8-9=32x+8-17=f(x)-17.

This shows that the shift down is made by 17 units.

Answer: 17 units

4 0
3 years ago
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Bernite is selling candy bars for a school fundraiser. The school paid $20.00 for a box of 15 king-size candy bars and Bernite s
irina1246 [14]

Answer:

Step-by-step explanation:

candy sold vs money earned

money earned =  2 dollars * number of bars sold- cost of bars

money earned = 2 b -20

this is an equation of a line

(y= 2x-20)  

A.The relationship is linear    true

B.The relationship is nonlinear   false

C.The relationship is always results in a negative profit   false

it crosses the x axis at 10 candy bars

D.The relationship always result in a positive profit   false

it crosses the x axis at 10 candy bars

E.The relationship is proportional   false

F.The relationship is non-proportional  true  it is a line that does not cross the origin

1jaiz4 and 21 more users found this answer helpfulcandy sold vs money earned

money earned =  2 dollars * number of bars sold- cost of bars

money earned = 2 b -20

this is an equation of a line

(y= 2x-20)  

A.The relationship is linear    true

B.The relationship is nonlinear   false

C.The relationship is always results in a negative profit   false

it crosses the x axis at 10 candy bars

D.The relationship always result in a positive profit   false

it crosses the x axis at 10 candy bars

E.The relationship is proportional   false

F.The relationship is non-proportional  true  it is a line that does not cross the origin

3 0
2 years ago
Exercise 3.5. For each of the following functions determine the inverse image of T = {x ∈ R : 0 ≤ [x^2 − 25}.
masya89 [10]

a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

b. The inverse image of g(x) is g^{-1}(x) = e^{x}

c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

<h3 /><h3>The domain of T</h3>

Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0

⇒ x² ≥ 25

⇒ x ≥ ±5

⇒ -5 ≤ x ≤ 5.

<h3>Inverse image of f(x)</h3>

The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

f : R → R defined by f(x) = 3x³

Let f(x) = y.

So, y = 3x³

Dividing through by 3, we have

y/3 = x³

Taking cube root of both sides, we have

x = ∛(y/3)

Replacing y with x we have

y = ∛(x/3)

Replacing y with f⁻¹(x), we have

So,  the inverse image of f(x) is f⁻¹(x) = ∛(x/3)

<h3>Inverse image of g(x)</h3>

The inverse image of g(x) is g^{-1}(x) = e^{x}

g : R+ → R defined by g(x) = ln(x).

Let g(x) = y

y =  ln(x)

Taking exponents of both sides, we have

e^{y} = e^{lnx} \\e^{y} = x

Replacing x with y, we have

y = e^{x}

Replacing y with g⁻¹(x), we have

So, the inverse image of g(x) is g^{-1}(x) = e^{x}

<h3>Inverse image of h(x)</h3>

The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

h : R → R defined by h(x) = x − 9

Let y = h(x)

y = x - 9

Adding 9 to both sides, we have

y + 9 = x

Replacing x with y, we have

x + 9 = y

Replacing y with h⁻¹(x), we have

So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

Learn more about inverse image of a function here:

brainly.com/question/9028678

5 0
2 years ago
Help me please in urgent
Stells [14]

Answer:

A

Step-by-step explanation:

20 times 10% is 2

7 0
2 years ago
Suppose ΔJKL≈ΔQRS. Which statement can you conclude?
ladessa [460]
D is the answer.....


Where are the moderators right now for brainly???????
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3 years ago
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