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maw [93]
3 years ago
5

Please help me with this also if you may, Tell me how you got what you got. Worth a lot of points :)

Mathematics
1 answer:
lesantik [10]3 years ago
4 0

Answer

Step-by-step explanation:

i need the form of opperations what are you doing? standard form algerbraic roots with mixed fractions?

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1/16^3x=64^2(x+8)<br> Solve for x.
SSSSS [86.1K]

Answer:

x = -4

Step-by-step explanation:

16 = 4*4 = 4²

64 = 4 * 4* 4 = 4³

(\dfrac{1}{16})^{3x}=64^{2*(x+8)}\\\\\\(16^{-1})^{3x}=64^{2x + 16}\\\\\\16^{-3x}=64^{2x +16}\\\\(4^{2})^{-3x}=(4^{3})^{2x+16}\\\\4^{-6x}=4^{6x +48}

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