3 years ago

Solve system of equations 14x + y = -4 and y = 3x^2 - 11x - 4

Mathematics

1 answer:

Keith_Richards [23]3 years ago

7 0

Hello here is a solution :

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Simplify (x − 4)(3x2 − 6x + 2). 3x3 + 6x2 − 22x + 8 3x3 − 18x2 + 26x − 8 3x3 − 18x2 − 22x − 8 3x3 + 6x2 + 22x + 8

Eduardwww [97]

Step-by-step explanation:

you know the answerv noow

7 0

4 years ago

I need help it is due tonight

ddd [48]

Answer:

2) x= 1/2

3) x= 1/2

4) x= 1/2

5) x= 1/10

6) x=2/3

7) x= 3/4

8) x= 1/3

9) x= 5/9

Also use Math_way ^_^

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3 years ago

G(x) = -10x – 8 a function

wlad13 [49]

Answer:

yes that is a function and not an equation

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3 years ago

A train travels a distance of 60 km at uniform speed. If the speed of the train was reduced by 10 kmh-1, the time taken to trave

tester [92]

Answer:

Initial speed is 32 m/s

At uniform speed, acceleration is 0, (a = 0).

When speed reduced, (v - u) = 2.78 ms-¹, t = 1800 sec, s = 60 ,000 metres.

From first equation of motion:

${ \boxed{ \bf{v = u + at}}} \\ { \tt{(v - u) = at}}$

substitute:

${ \tt{2.78 = (a \times 1800)}} \\ { \tt{acceleration = 0.0015 \: {ms}^{ - 2} }}$

from second equation of motion:

${ \boxed{ \bf{s = ut + \frac{1}{2} a {t}^{2} }}}$

substitute:

${ \tt{60000 = 1800u + ( \frac{1}{2} \times 0.0015 \times {1800}^{2}) }} \\ { \tt{1800u = 57570}} \\ { \tt{u = 32 \: m {s}^{ - 1} }}$

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3 years ago

Enlarge the triangle by scale factor 0.5 using 3,1 as the centre of enlargement

NISA [10]

Answer:

the points are :

(0,-1)

(0,0)

(-1,3)

(If you are using MathsWatch) For this question the triangle gets smaller so i'm not sure why it says Enlarge the triangle.

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3 years ago