<em>A</em><em>+</em><em>2</em><em>2</em><em>°</em><em>=</em><em>9</em><em>0</em><em>°</em><em> </em><em>(</em><em>SUM</em><em> </em><em>OF</em><em> </em><em>COMPLEMENTRY</em><em> </em><em>ANGLES</em><em> </em><em>)</em>
<em>A</em><em>=</em><em>9</em><em>0</em><em>°</em><em>-</em><em>2</em><em>2</em><em>°</em>
<em>A</em><em>=</em><em>6</em><em>8</em><em>°</em><em> </em><em>ANSWER</em><em>.</em>
Yes, the sampling distribution is normally distributed because the population is normally distributed.
A sampling distribution is a chance distribution of a statistic obtained from a larger variety of samples drawn from a specific populace. The sampling distribution of a given population is the distribution of frequencies of a variety of various outcomes that would probable occur for a statistic of a populace.
A sampling distribution is a probability distribution of a statistic this is obtained via drawing a huge variety of samples from a particular populace. Researchers use sampling distributions so that you can simplify the technique of statistical inference.
Solution :
mean = μ40
standard deviation σ σ= 3
n = 10
μx = 40
σ x = σ√n = 3/√10 = 0.9487
μ x = 4σ\x = 0.9487
σx = 0.9487
Yes, the sampling distribution is normally distributed because the population is normally distributed.
Learn more about sampling distribution here:- brainly.com/question/12892403
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Answer:
Step-by-step explanation:
(x - 2)/2 = 4
x - 2 = 8
x = 10
(y + 2)/2 = -3
y + 2 = -6
y = -8
(10, -8)