We have been given that a particular type of cell increases by 75% in number every hour. We are asked to find the number of cells present at the end of 12 hours if there are initially 4 of these cells.

We will use exponential growth formula to solve our given problem.

$y=a\cdot (1+r)^x$ , where,

y = Final amount,

a = Initial amount,

r = Growth rate in decimal form,

x = Time.

$75\%=\frac{75}{100}=0.75$

Upon substituting initial value $a=4$ and $x=12$ in above formula, we will get:

$y=4\cdot (1+0.75)^{12}$

$y=4\cdot (1.75)^{12}$

$y=4\cdot 825.0050068497657776$

$y=3300.020027$

$y\approx 3300$

Therefore, there will be approximately 3300 cells at the end of 12 hours.

5 0

3 years ago

Select the situation that describes the following expression.<br>co<br>alယ

Mazyrski [523]

Answer:

what are the things at the end.

Step-by-step explanation:

8 0

3 years ago

Please help me thanks

stich3 [128]

Answer:

5. 26⁰F, rise

6. 0, Added both the numbers instead of subtracting

7. 10⁰C

8. 25⁰F

9. 13⁰F

10. -4

5 0

2 years ago