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2 years ago

9

PLEASEEE HELP ME PLEASEE!!

1 answer:

pogonyaev2 years ago

7 0

The 3rd one i’m pretty sure

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HELPHELPHELP im on a timer

mr Goodwill [35]

8 is (7+4)/(7+4+5+9) = 11/25 = 0.44

9 is 5/(5+7) = 5/12 = 0.417 so I'm sorry I can't help with that one

5 0

2 years ago

Use the number 913,256 Write the name of the period that has the digits 913.

Alborosie

Thousand - units, tens, hundreds, etc

913,000

7 0

2 years ago

How do you know a number is divisible by 5?

djverab [1.8K]

The last number will either be 5 or 0. For example 15, or 20.

7 0

2 years ago

Read 2 more answers

Daniela is a stain glass artist; she created the window below for her living room. What is

OLga [1]

The window has a shape of a semi-circle (half of a circle).

We know the diameter d = 12 ft.

The area of a (complete) circle is given by the formula:
A = π × r²

The radius can be found by halving the diameter:
r = d ÷ 2
= 12 ÷ 2
= 6 ft

Therefore the area of the circle will be:
<span>A = π × r²
= 3.14 × 6</span>²
= <span>3.14 × 36
= 113.04 ft²

And the area of the semi-circle:
A = </span><span>113.04 </span>÷ 2
= 56.52 ft²

Hence, the area of the window will be 56.52 ft².

3 0

2 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

2 years ago