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3 years ago

2. What is the difference if 0.915 is taken from 2.31?

Mathematics

1 answer:

Bezzdna [24]3 years ago

7 0

A. 1.395
2.31 - 0.915 = 1.395

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Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and

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Given Information:

Population proportion = p = 0.55

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Answer:

$\sigma_1 = 0.091$

$\sigma_2 = 0.050$

$\sigma_3 = 0.016$

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$\sigma = \sqrt{\frac{p(1-p)}{n} }$

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$\sigma_1 = \sqrt{\frac{p(1-p)}{n_1} }$

$\sigma_1 = \sqrt{\frac{0.55(1-0.55)}{30} }$

$\sigma_1 = 0.091$

For sample size n₂ = 100

$\sigma_2 = \sqrt{\frac{p(1-p)}{n_2} }$

$\sigma_2 = \sqrt{\frac{0.55(1-0.55)}{100} }$

$\sigma_2 = 0.050$

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$\sigma_3 = \sqrt{\frac{p(1-p)}{n_3} }$

$\sigma_3 = \sqrt{\frac{0.55(1-0.55)}{1000} }$

$\sigma_3 = 0.016$

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

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