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zepelin [54]
3 years ago
11

Help pls and thank you:)

Mathematics
1 answer:
Bas_tet [7]3 years ago
6 0
I think Z=16 I don’t know exactly sorry
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If 3(d+1)=4(d–2)<br> then what is the value of 5(d–2)
Sonja [21]

Answer:

5(d - 2) = 45

Step-by-step explanation:

Solve the given equation for d

3(d + 1) = 4(d - 2) ← distribute parenthesis on both sides

3d + 3 = 4d - 8 ( subtract 3d from both sides )

3 = d - 8 ( add 8 to both sides )

11 = d

Then

5(d - 2) = 5(11 - 2) = 5(9) = 45

3 0
2 years ago
PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
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